here is my email : alfante.alfante@gmail.com

Thanks!!

my paper is on next week

Thanks
Igor

sorry for mi english.

Thanks a lot buddy .. :-)

Cheers :-)

I think why the answer of the Q3 might be D is because its asking of “in how many different frames will the packet be encapsulated as it is sent across the internetwork?”, I think here’s the tricky question “as it is sent across the internetwork” not to include the Host.

I hope I\m right as I will be sitting tomorrow for my exam and I’ll answer D to this question if I run into it.

I pray to GOD to pass it as I’ve studied long.

Frames are the PDUs of the DataLink layer, wich service the cominucation on LOCAL networks. The packet (layer 3′s PDU) has to be encapsulated 3 times to get to server 1, for it has to go through 3 diferent networks.

If you dint get it that way, try to look at it this way.

First encapsulation happens to send the packet from host 1 to router 1. This is posible because of the comunication ocurring on the datalink layer, with the mac addresses of Host 1 and Router1.

After this, router 1 recieve the frame, and internally sends it to the network layer, process it, and sends it to the right interface. That’s when…

Second encapsulation happens!!! To send the packets from R1 to R2, the packets need to be encapsulated with the mac addresses of R1 and R2. router 2 recieve the frame, and internally sends it to the network layer, process it, and sends it to the right interface.

The third encapsulation occurs here, to send the packets from R2 to SRV1, with the mac addresses of each devices’ interfces.

camillo_@libero.it

I would thank you in advance.

Instead of all of you WHINERS worrying if you have studied the exact right dumps to memorize the exact right answers that you expect to find on your exact version of the exam on the exact day you take it, you should try, like this Dude, to understand the Internetworking concepts that the 9tut practice exam material is showing you.

There is no “magic” or “trick” to this question for those who understand the material.

The question is about passwords. If the link in question uses HDLC, the answer is none, since HDLC doesn’t use authentication. If the link in question uses PPP, the answer may also be none, as PPP does not REQUIRE the use of authentication, but authentication MAY be configured, if desired.

One of the links above (NorthCentral, Se1/3) is configured PPP with CHAP authentication. If your version of the exam asks you to identify a password that would be required to establish a connection between NorthCentral and a router in another Branch, you who understand the material know that CHAP expects to find the HOSTNAME of the router in the other Branch configured in a “Username HOSTNAME password SHAREDPW” global command in the Running-Config of NorthCentral. Conversely, the router HOSTNAME has a “Username NorthCentral password SHAREDPW” global command configured. The answer, in that case, is “SHAREDPW”.

So, all you whiners STOP OBSESSING about having memorized all the correct answers or not, you are making me SICK. Instead, LEARN THE MATERIAL, and use 9tut to polish up on practicing exam execution, how to take an exam.

This is not a frame relay question but rather a ppp authentication question. Recall that ppp authentication uses pap and chap. If a password exists it will be listed in the running config under the hostname line. This will have a username (name of the router) and a password that that matches for each router.
Q4 references router (MidEast), the “run config” shows that interface s1/1 does not use “encapsulation ppp” & “ppp encapsulation chap” or pap, thus no need for a password. If no encapsulation is listed under an interface than Cisco default encapsulation is assumed (HDLC).

Here are some examples of ppp authentication for PAP and CHAP:

PAP example between R1 & R3

run config on R1:

hostname R1
username R3 password C0nsole
!
int serial 0/0
ip address 128.0.1.1 255.255.255.0
encapsulation ppp
ppp authentication PAP
ppp pap sent-username R1 password C0nsole

run config on R3:

hostname R3
username R1 password C0nsole
!
int serial 0/0
ip address 128.0.1.2 255.255.255.0
encapsulation ppp
ppp authentication PAP
ppp pap sent-username R3 password C0nsole

CHAP example between R1 & R3:

run config on R1:

hostname R1
username R3 password C0nsole
!
int serial 0/0
ip address 128.0.1.1 255.255.255.0
encapsulation ppp
ppp authentication CHAP

run config on R3:

hostname R3
username R1 password C0nsole
!
int serial 0/0
ip address 128.0.1.2 255.255.255.0
encapsulation ppp
ppp authentication CHAP

**note
encapsulation ppp by itself does not need a password, it has to be accompanied by the “ppp authentication” command.

Bottom line – if question 4 asks for some router, look at the router and find the interface in the run config, if it has ppp authentication chap or pap, look at the top of the run config for the password.

Question no # 4. (FR)

What is the correct answer? Please help coz I’m totally confuse with the explanation given.

Thanks

Cheers :-)

…How many different frames? Three.
How many different encapsulation types? Two.

Answer is: D

https://learningnetwork.cisco.com/thread/54220

amirakclubs@gmail.com

thanks

Thank you

Which question?

COOOL! Thanks a lot if i get this question i will mark D as an answer :D

Exactly! Thus, if answer B was the right answer, it should have stated:

“R1 will drop this packet because it is configured to drop directed boradcast packets”.

Since the reason provided is not valid, the response is wrong. And then the only viable answer remains D

Thats what i thought. However in my opinion this question is not completely valid, as routers by default are dropping direct broadcasts and there is nothing said that this option is enabled. Would you agree?

The directed broadcast address IS a valid IP address (not a valid HOST address, but a valid IP address). It is used in different situations (e.g. DHCP relay). Thus, answer B is wrong.

The correct answer is “D”. The directed broadcast work by encapsulating the packet Layer2 broadcast frame (destination MAC FFFFFFFF), which will contain the frame within the broadcast domain. This is exactly answer D.