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when an access-list is applied to inbound packets on an interface, those packets are processed through the access-list before being routed to the outbound interface, whereas an access-list applied to an outbound packets on an interface, packets are routed to the outbound interface and then processed through the access-list before being queued

can some1 elaborate,confuse..

subnet 192.168.176.0
hosts per subnet 8-2 = 6
block size 8 because the mask is 21

subnet = 192.168.176.0
host range = 192.168.176.1 – 192.168.183.254 (B falls in this range)
broadcase =192.168.183.255

Qn 8 : A network interface port has collision detection and carrier sensing enabled on a shared twisted pair network. From this statement, what is known about the network interface port?

In sw have CSMA/CD and also communicate in full duplex but how answer could be the half duplex ?

mesaa el fol ya m3lmeen

is 9 tut the latest question ,iwill have exam 1st of february

how many question in 9tut

Today I have passed the CCNA. (860/825)
50 questions 3 labs (VTP, EIGRP, ACL). 35 from 9tut.

Also thanks a lot Brar and Sekhar (still valid from examcollection)

Ty again 9tut

from here none

I didn’t have look closely at the exhibition

have a look at the screenshot

http://i47.tinypic.com/mtw7xd.png

according to dumps I have correct is , WHY?? why is not switch3, maybe it’s just my bad understanding of the question.

199.99.9.40 through 199.99.9.62

40 + x = 62

40 +22 = 62

so any number between 40 and 62 (199.99.9.40 – 199.99.9.62) will work as a source address.

Among the choices: /29 or /27 which are serial interfaces it will send to the higher “/” number in this case it is /29 so you would choose 10.1.5.64 /29 over the other.

according 2 d routing table, whr vll d router send a packet destined for 10.1.5.65 ?

N/W Intrfce Nxt-hop

10.1.1.0/24 e0 directly connctd
10.1.2.0/24 e1 ”
10.1.3.0/25 s0 ”
10.1.4.0/24 s1 ”
10.1.5.0/24 e0 10.1.1.2
10.1.5.64/28 e1 10.1.2.2
10.1.5.64/29 s0 10.1.3.3
10.1.5.64/27 s1 10.1.4.4

1) 10.1.1.2
2) 10.1.2.2
3) 10.1.3.3
4) 10.1.4.4

original source IP is some IP of the host from network 10.10.0.0/24, translated by router using NAT to IP from configured range: 199.99.9.40 – 199.99.9.62, so it could be any IP from this range, answer is 199.99.9.57.

IN THE CCNA EXAM, CAN WE SKIP ANY UNKNOWN ANSWER ? OR DO WE HAVE TO ANSWER ALL FROM 1 TO 50 QUESTIONS CONTINUOSLY WITHOUT SKIP ?

THANKS

Can someone pls post which interfaces in the diagram will be DP and BLK ports for all the switches

Thanks

dnt u think the ans should be “D.four” as a switch as a whole also contribute to broadcast domain ie. the trunk, the two switches as 1 broadcast domain & the three vlans as three different broadcast domains………so total 4 broadcast domains……………
plz help…..i hv my xm in few days……….dnt want to fail coz of silly mistakes……tnx

To determine the designated port on a network segment, we should first see which switch has the lowest cost to root bridge. In the event of a tie, only then will the lowest BID be used.

http://www.omnisecu.com/cisco-certified-network-associate-ccna/how-spanning-tree-protocol-stp-select-designated-port.htm

For this qn, the path cost is ambiguous because the port types are not specified. But if you assume all links are same speed, then Switch 3 has the lowest cost path to root bridge (hence the answer).

Can any expert verify my point?

vipin.heat@gmail.com
vipin.heat@yahoo.com

They’re combined to network 172.1.4.0, host 172.1.4.0 – 172.1.4.254, next network 172.1.5.0
Block size is 256, so mask is /24 > 255.255.255.0

Refer to the exhibit. Which switch provides the spanning-tree designated port role for the network segment that services the printers?

at the end of the explanantion
(Please notice that Switch 1 will become the root bridge because of its lowest priority, not Switch 3)

what is really the answer Sw1 or Sw3

The output is from a router in a large enterprise. From the output, determine the role of the router.

Router A# show ip route
Codes: C – Connected, S – Static, I – IGRP, M – mobile, B – BGP
.
.
.
.
.
Gate of last resort is 0.0.0.0 to network 0.0.0.0
172.16.0.0/24 is subnetted, 1 subnets
C 172.16.1.0 is directly connected, Ethernet0/1
10.0.0.0/30 is subnetted, 1 subnets
C 10.255.255.255.200 is directly connected, Serial0/0
S* 0.0.0.0/0 is directly connected, Serial 0/0
RouterA#

(A) A Core Router
(B) The HQ Internet gateway router
(C) The WAN router at the central site
(D) Remote stub router at a remote site.

I believe option F for Q9 is correct ans

48 ques for exams including 3 simulation, I had EIGRP, Acesslist2 and VTP. Make sure the practice the simulation, use packet tracer or gns3. Best wishes to all!

Everything you’ve read so far dealt with half-duplex operation (CSMA/CD, back-off timers, and so on). Full-duplex mode allows stations to transmit and receive data simultaneously. This makes for more efficient use of the available bandwidth by allowing open access to the medium. Conversely, this mode of operation can function only with Ethernet switching hubs or via Ethernet cross-over cables between interfaces capable of full-duplex Ethernet. Full-duplex mode expects links to be point-to-point links. There are also no collisions in full-duplex mode, so CSMA/CD is not needed.