Comments on: CCNA – Subnetting Questions 2

By: Padmaja

Padmaja — Tue, 25 Nov 2014 05:03:19 +0000

For question 7, how can class c address 192.0.2.0 use /23 subnet mask? Class c can use only from /24 onwards. Pls clarify.

By: Anonymous

Anonymous — Thu, 19 Jun 2014 16:58:31 +0000

@xallax

You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while proving the maximum number of subnets. Which network address and subnet mask meet this requirement?

A-192.168.252.8 255.255.255.252
B-192.168.252.16 255.255.255.252
C-192.168.252.8 255.255.255.248
D-192.168.252.0 255.255.255.252
E-192.168.252.16 255.255.255.240

in this questions why they choose answer C not A or D can you clearfy it?

248 sobran 3 bits para hosts

By: vinu

vinu — Fri, 14 Mar 2014 11:08:31 +0000

I passed my CCNA 200-120 yesterday with score 1000/1000.
The sim is Access-list 1 , Access-list 2 & EIGRP.
Thanks 9tut. I made it.

By: sararoma

sararoma — Wed, 02 Oct 2013 09:01:08 +0000

I had passed my exam 841/1000 i’m so very happy end satisfaction, thanks guys
i done ACL’S, EIGRP, VTP lab, were same that the Lam here.
thanks a lot

By: lukin

lukin — Tue, 24 Sep 2013 03:42:26 +0000

this is address 192.168.5.33 /28
but the subnetmask is /28 = 255.255.255.240
the hop is 0-16-32-48-64……
the address ip for the dhcp is 192.168.5.33.
ip valid 192.168.5.33 to 192.168.5.47

By: samit khan

samit khan — Sun, 22 Sep 2013 22:23:16 +0000

Can any bdy plz explain Q9, how c is the answer

By: Abs619

Abs619 — Sun, 22 Sep 2013 11:30:55 +0000

kb8…… Thanks a lot buddy… Now I understand :-)

Cheers :-)

By: Waymond

Waymond — Tue, 17 Sep 2013 23:58:05 +0000

@Anas Salo

Could you please specify why your answers are correct on Q10 please? Thank you.

By: ndane

ndane — Tue, 17 Sep 2013 13:48:40 +0000

any thing important for some of us who preparin g to tape the exam

By: kb8

kb8 — Mon, 16 Sep 2013 02:57:25 +0000

Abs619

From the Subnet mask 255.255.254.0, you care about the third octet (254) convert that to binary 11111110

From that you know that the increment is 2. ( 128 64 32 16 8 4 {2} 1). Remember, all you care about are the last two octets, so the increment will be X.X.2.0 – X.X.4.0 – X.X.6.0 and the last IP address cannot be assigned as it is reserved for Broadcast, so the only assignable IP addresses within the 2.0 and 4.0 are 3.0 and 2.255 as the broadcast will be 3.255.

By: Abs619

Abs619 — Sun, 15 Sep 2013 06:22:17 +0000

Can anybody explain how to calculate correctly

Question 10

Which two addresses can be assigned to a host with a subnet mask of 255.255.254.0? (Choose two)

A. 113.10.4.0
B. 186.54.3.0
C. 175.33.3.255
D. 26.35.2.255
E. 17.35.36.0

Answer: B D

By: Barath Aravindh

Barath Aravindh — Fri, 13 Sep 2013 16:26:56 +0000

Can any one explain Q10

By: Anonymous

Anonymous — Fri, 13 Sep 2013 10:12:53 +0000

it is bra matt damon

By: clement21

clement21 — Thu, 12 Sep 2013 19:45:15 +0000

Isn’t stil actual 640-802?

By: jasostrong

jasostrong — Wed, 11 Sep 2013 13:40:02 +0000

Thanks 9tut. I made it. I passed my CCNA 200-120 today. The sim is Access-list 1 , Access-list 2 & EIGRP. A lot of new questions like Netflow, Syslog, SNMP, VRRP, and GLBP.

By: Anonymous

Anonymous — Wed, 11 Sep 2013 03:22:46 +0000

yes except not the last address or broadcast address

By: Akshay Handa

Akshay Handa — Sun, 08 Sep 2013 09:47:43 +0000

Please answer my questions anyone…!!! Waiting for your reply…!!!

By: immy

immy — Fri, 06 Sep 2013 20:17:27 +0000

@thomas, please would you brief me a bit after your exams then, on how the exam is, since I will be writing too on friday that same week, wishing you best of luck… immyrichardson@yahoo.com

By: thomas bulloch

thomas bulloch — Mon, 02 Sep 2013 16:08:43 +0000

640-802 exam book next tuesday scared lol been studying hard for this hope i am rewarded any advice would be nice.

thomasbulloch1988@gmail.com

By: dstul

dstul — Mon, 02 Sep 2013 14:22:47 +0000

About q 6
The ip subnet zero is a default setting in Cisco IOS, according to Wendell Odom’s books. So I think that the correct answer is B.

By: Anonymous

Anonymous — Mon, 02 Sep 2013 09:50:15 +0000

q. 8 in exam

By: Akshay Handa

Akshay Handa — Fri, 30 Aug 2013 17:36:25 +0000

The value of Default gateaway can be anything within the same network…????

By: Akshay Handa

Akshay Handa — Fri, 30 Aug 2013 17:33:52 +0000

You mean to say if suppose anyip address is given 192.168.93.97 255.255.255.240…..then i should choose default gateaway ( router) be 192.168.93.110….in case of switch vlan be 192.168.93.97……Is that right..???

By: Dave C

Dave C — Wed, 28 Aug 2013 22:07:55 +0000

Not sure what you mean. The DG is normally an IP address within the same subnet as the host but applied on a different device. I normally give the switch VLAN the first IP address and the DG (router) the last, this will allow clients on the subnet to have consecutive IP addresses. Depends totally on your network layout.

By: Akshay Handa

Akshay Handa — Wed, 28 Aug 2013 04:07:19 +0000

Hello guys,

Please explain me how to choose the default gateaway..is there any criteria..??

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By: sandip

sandip — Sun, 25 Aug 2013 13:11:03 +0000

Q-7 having some mistake regarding calcution of the subnet
192.0.2.0 /29 subnet range 192.0.2.0 – 192.0.3.255 and subnet mask will be 255.255.255.254

By: Anas Salo

Anas Salo — Wed, 21 Aug 2013 13:30:43 +0000

Does this speak to me ؟

By: Anas Salo

Anas Salo — Tue, 20 Aug 2013 22:07:59 +0000

Please answer

Can you come questions of this exam?
The exam will be held next month
Is it difficult or easy exam??

By: Anas Salo

Anas Salo — Tue, 20 Aug 2013 21:44:01 +0000

Question 10 solution
A.113.10.4.0
B.186.54.3.0
C.175.33.3.255
D.26.35.2.255
E.17.35.36.0

solution :
the subnet mask 255.255.254.0 Means ( /23 ) .
We will check all IP address refer to the subnet mask .
In this question we will analyze the last 2 octets to Binary and select subnet mask On IP

A. 113.10.0000010[[0.00000000
It turns out after determining the subnet mask This IP is Network Address (can not be assigned)

B. 186.54.0000001[[1.00000000 (can be assigned)

C. 175.33.0000001[[1.11111111
It turns out after determining the subnet mask This IP is BC Address (can not be assigned)

D. 26.35.0000001[[0.11111111 (can be assigned)

E.17.35.0010010[[0.00000000
It turns out after determining the subnet mask This IP is Network Address (can not be assigned)

:. Answer B.D

By: rose

rose — Wed, 14 Aug 2013 23:33:03 +0000

thanks Rahman

By: chanaka

chanaka — Sun, 04 Aug 2013 08:06:05 +0000

nice work done by 9tut

By: Anonymous

Anonymous — Wed, 31 Jul 2013 12:31:01 +0000

Can u guys plz explain me the answer of last question?? i didnt get it

By: pearl

pearl — Wed, 24 Jul 2013 09:56:11 +0000

sorry, the networks are
10.0.0.0
10.0.1.0
10.0.2.0
10.0.3.0
and they are summarized with a class B mask bcos the network numbers are in the 3rd subnet i.e 255.255.252.0=3rd subnet.

By: pearl

pearl — Wed, 24 Jul 2013 09:51:02 +0000

for summarization, all that matters is the block size that’ll contain all the networks you wanta summarize.
10.0.0.0
10.1.0.0
10.2.0.0
10.3.0.0
from 0-3 is 4 numbers i.e. block size 4.now which class B maks offers a block size of 4? 255.255.252.0= /22. easy peasy

By: The Pig

The Pig — Mon, 22 Jul 2013 18:38:24 +0000

@ANON

The way I use to work out summarisation is this.

Q.4 has 4 subnets, so how many bits are needed for those subnets? 2×2 = 4 So 2 bits are required. Then simply take 2 from the original subnet mask (which you can tell is a /24) so 24-2 = 22 so its a /22 you use. If you have multiple subnets with different slash notations to summarise then use the lowest slash notation of those subnets.

Don’t know if its proven but its worked for me!

By: Anonymous

Anonymous — Mon, 22 Jul 2013 12:16:55 +0000

Hi 9tut,
I still don’t understand the explanation of question 4. Can you please explain clearly how we are moving two bits left? Thx

By: Vick

Vick — Sun, 21 Jul 2013 17:02:29 +0000

freinds please help me i wanna take the CCNA EXAM IN COMING DAYS
please send me last dumps in my email
vickakop@gmail.com
thanks in advance

By: ilan

ilan — Tue, 16 Jul 2013 09:09:55 +0000

q.10

how choose host ip address….
255.255.254.0 mean /23 we can use 512 ip address in one network with any of the series…

By: Rob

Rob — Thu, 11 Jul 2013 16:25:11 +0000

I’m still confused by Q4, i know a few people have posted solutions but they aren’t making any sense to me.

Can someone lay it out step by step please?

By: pat

pat — Wed, 10 Jul 2013 21:41:53 +0000

@raj

sorry the range of valid IPs is 192.168.5.33 – 192.168.5.47, increaments of 16 not 32, sorry about it

By: pat

pat — Wed, 10 Jul 2013 21:39:33 +0000

@Raj

we have the address of the default gateway 192.168.5.33/28 — this is valid IP address

/28 = 192.168.5.0
192.168.5.16
192.165.5.32
192.168.5.64 and so on, so we have increments of 16 as 192.168.5.0000|0000

our address is falling into 192.168.5.32 network, range of valid ip addresses is
192.168.5.33 – 192.168.5.62 note that 192.168.5.63 can’t be used as it is the last ip address in this subnet therefore is broadcast address

you should be able to answer the question now

By: pat

pat — Wed, 10 Jul 2013 21:31:50 +0000

at some point I got confused by question 4 too, dunno why
for those who are still confused, have a look at this

http://postimg.org/image/iojstw6hd/

By: Raj

Raj — Fri, 05 Jul 2013 06:34:48 +0000

Hi all,

Can anyone please help me working out with q9 and q10, please?

Thanks

By: rahman

rahman — Fri, 28 Jun 2013 20:02:01 +0000

The subnet is /28. so its 255.255.255.240. Subtract 255-240= 16.
So your every subnet has 16 host, but the first one is the default address and last is broadcast address.

The default network given is 192.168.5.33 , It means its that it belongs to 192.168.5.32 address group, from .33 to .47.

IN the given options only .40 satisfies the condition, hence its the only right answer.

By: Anonymous

Anonymous — Thu, 27 Jun 2013 08:34:16 +0000

Could give the explanation of question 9 ?
Why .40 specific
Why notr .14 or .55???

Network address: .16 .32 .48 .60 .76 .92
Broadcast address: .15 .31 .47 .59 .75 .91

Thank you in advance for your help.

By: Richtoe

Richtoe — Mon, 24 Jun 2013 19:11:21 +0000

Can someone expline thie please -
Question 9

The network default gateway applying to a host by DHCP is 192.168.5.33/28. Which option is the valid IP address of this host?

A. 192.168.5.55
B. 192.168.5.47
C. 192.168.5.40
D. 192.168.5.32
E. 192.168.5.14

Why is answer .40

By: sabyasachi

sabyasachi — Fri, 21 Jun 2013 13:30:22 +0000

Hi
I couldn’t understand how ’255′ is added to an ip address “175.33.3.255″ in class B/A and is assigned to a network . Please help…

By: sunday

sunday — Tue, 18 Jun 2013 18:10:56 +0000

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By: sunday

sunday — Tue, 18 Jun 2013 18:09:53 +0000

Can someone plzz send me the latest dumps I’m writting on the 23rd this month thanx so much 9tutzeeeeeey

By: Ruth

Ruth — Thu, 13 Jun 2013 17:39:45 +0000

If you write 255.255.254.0 in binary you get 11111111.11111111.11111110.00000000
so focusing on the third octet the ranges will be x.x.0.0 – x.x.1.255 (where x can be any value because we are interested in the third and fourth octet) so we have for ranges for the third and fourth octet only:
.0.0 – .1.255
.2.0 – .3.255
.4.0 – .5.255
.6.0 – .7.255
.8.0 – .9.255
.10.0 – .11.255
You know you cannot use the first number because it is the network number and the last number because it is the broadcast. Any numbers that does not fall into this 2 categories will be used by hosts.

By: David Okeri

David Okeri — Wed, 05 Jun 2013 08:51:59 +0000

Pliz i will sit for the CCNA exam next month, can someone send me the latest dumps on email: olesimbe@yahoo.com

By: correction

correction — Tue, 04 Jun 2013 05:18:20 +0000

I mean….@needs help….if we don’t enable 0th subnet then the 1st subnet will be 172.16.0.4 so increment is 4…the last bit in /30…….
172.16.0.4
172.16.0.8
172.16.0.12
.
.
so 18th subnet ….will be 172.16.0.72
usable ip 172.16.0.73 – 172.16.0.74

By: Anonymous

Anonymous — Tue, 04 Jun 2013 05:16:48 +0000

@needs help….if we don’t enable 0th subnet then the 1st subnet will be 172.16.0.0 so increment is 4…the last bit in /30…….
172.16.0.4
172.16.0.8
172.16.0.12
.
.
so 18th subnet ….will be 172.16.0.72
usable ip 172.16.0.73 – 172.16.0.74

By: Needs help

Needs help — Wed, 29 May 2013 03:49:16 +0000

Hello everybody! i will be thankful if somebody can help to determine the answer for
“What will be the 18th subnet of 172.16.0.0/30?”
and usable ip.

Thanks a lot

By: kk

kk — Mon, 20 May 2013 13:41:11 +0000

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By: saurabh kukreja

saurabh kukreja — Thu, 09 May 2013 09:02:44 +0000

so easy…

By: John

John — Fri, 03 May 2013 08:36:45 +0000

Can someone please send me the latest dumps to sg980321@hotmail.com. Thank you in advance!!

By: itzjohn

itzjohn — Thu, 25 Apr 2013 17:08:56 +0000

@ yaser

Those are the correct answers.

E. Access-list 10 permit ip 192.168.148.0 0.0.1.255

Lets change the wild card mask to a subnet mask.
0.0.1.255 is the same as 255.255.254.0 = (510 host)

This ACL covers 192.168.148.1 – 192.168.149.255
Meaning it cover both 192.168.148.0 & 192.168.149.0 networks.

——————————————————————————————-

F. Access-list 10 permit ip 192.168.146.0 0.0.1.255

Lets change the wild card mask to a subnet mask.
0.0.1.255 is the same as 255.255.254.0 = (510 host)

This ACL covers 192.168.146.1 – 192.168.147.255
Meaning it cover both 192.168.146.0 & 192.168.147.0 networks.

——————————————————————————————-

Using both these two ACL will cover all 4 networks.

By: Vikash

Vikash — Sun, 14 Apr 2013 11:49:33 +0000

Can some send the latest dumbs on below gven address:
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Thanks

By: golu

golu — Sun, 14 Apr 2013 07:14:51 +0000

Q-9 solved

By: golu

golu — Sun, 14 Apr 2013 07:06:20 +0000

PLS SOME EXPLAIN Q-9

By: Pasu

Pasu — Sat, 13 Apr 2013 07:02:08 +0000

@Raj
Question 10.

A. 113.10.4.0 (Its a network number whose broadcast address is 113.10.7.255. So, it cant be assigned as host)

B. 186.54.3.0(This is a valid host whose network number is 186.54.0.0 and broadcast is 186.54.3.255)

C. 175.33.3.255(It’s not a valid host because it’s a broadcast number for the network 175.33.0.0)

D. 26.35.2.255(It’s a valid host whose network number is 26.35.0.0 and broadcast is 26.35.3.255)

E. 17.35.36.0(It’s not a valid host because it’s a network number whose broadcast is 17.35.39.255)

I hope this will help.
Please correct me if I am wrong somewhere.

By: RAJ

RAJ — Sat, 13 Apr 2013 05:19:59 +0000

PLS SOME EXPLAIN Q10

By: Netzis

Netzis — Wed, 03 Apr 2013 01:36:13 +0000

@Yaser
Wildcard of 0.0.1.255 = subnet of 255.255.254.0 = CIDR /23 which covers 2 times /24 ranges.
Only necessary because you are being limited to 2 lines in the ACL instead of 4.

Can check with binary calculation: host address AND subnet mask = network address

e.g. 147 = 10010011, 254 = 11111110, do an AND operation and you get 146 i.e. 192.168.146.0 so you see you are covered for 192.168.146.0-192.168.147.255

By: Pasu

Pasu — Wed, 27 Mar 2013 06:48:04 +0000

@Yaser
I dont think answer is E and F because /24 will not have wildcard mask of 0.0.1.255
Wild card mask of /24 is 0.0.0.255

By: Yaser Arafat

Yaser Arafat — Sat, 23 Mar 2013 14:08:18 +0000

A network administrator is configuring ACLs on a Cisco router, to allow IP access form the 192.168.146.0/24,192.168.147.0/24,192.168.148.0/2,. and 192.168.149.0/24 networks only. Which two ACLs, when combined, should be used.

A.access-list 10 permit ip 192.168.146.0 0.0.0.255
B.access-list 10 permit ip 192.168.146.0 255 255.255.0
C.access-list 10 permit ip 192.168.147.0 0.0.255 255
D.access-list 10 permit ip 192.168.149.0 0.0.255.255.0
E.access-list 10 permit ip 192.168.148.0 0.0.1.255
F.access-list 10 permit ip 192.168.146.0 0.0.1.255

answer :E F
can anybody explain to me this one? Thanks!

By: Needs Help

Needs Help — Thu, 21 Mar 2013 18:17:46 +0000

Can someone please send me the latest dumps to kimms12@gmail.com. Thank you in advance!!

By: Michael

Michael — Tue, 19 Mar 2013 12:29:00 +0000

Question 4 in my exam 640-802

By: Syed Kashif Shahab

Syed Kashif Shahab — Tue, 19 Mar 2013 06:17:24 +0000

Q 10;

simple understanding for question 10. the question asked is 255.255.254.0. The play is in the thrid octet ’254′ which has 7 bits having an increment of 2…. like 128–64–32–16–8–4–2–1.
the bits taken from 128 to 2….so the magic number that i call the rightmost bit is 2. Now create the ranges as following..

increment 2:
beginning scope with the increment of 2.
0.0——-
2.0——-
4.0——
6.0——
8.0——-

The last IP is 0.255-1=254 usable ip i.e. x.x.x.254 likewise The last IP is 2.255-1=254 usable ip i.e. x.x.x.254 so we will write like this..

0.0——-1.255
2.0——-3.255
4.0——5.255
6.0——7.255
8.0——-9.255
36.0—–37.255

Now check from the given ip list which comes under these subnets. remember not to use subnet id or broadcast id as they are not assignable ips…i.e. for example for subnet 2.0——-3.255 2.1 >>>>>>2.1 —– 3.254 are usable IPs.

By: ben

ben — Sun, 17 Mar 2013 17:53:32 +0000

@mista, 26.35.2.255? is this the first usable ip.. i think wrong.
the first usable ip should be 26.35.2.1 ; usable ip are from 26.35.2.1 to 26.35.3.254

By: mista

mista — Fri, 15 Mar 2013 11:58:02 +0000

the mask 255.255.254.0 is for /23
so the network range will be for example 26.35.2.0-26.35.4.0
broadcast mask will be 26.35.3.255 and so the first host will be 26.35.2.255
remember 256-254 you get 2.. the subnets will be 0,2,4,6,8….

By: Yoly

Yoly — Wed, 13 Mar 2013 02:21:48 +0000

So how do you find which IP could be assigned?

By: ben

ben — Mon, 11 Mar 2013 14:47:34 +0000

Hi Mohamed,

the difference is that, 255.254.0.0. -> .254 is belong to 2nd octet and the it has /15 notation. while the 255.255.254.0 -> .254 is belong to 3rd octet which have a /23 notation.

By: Mohamed

Mohamed — Mon, 04 Mar 2013 10:19:29 +0000

Thanks MH.

Is the Mask 255.254.0.0 or 255.255.254.0 I am confused. Could u please explain me thanks.

By: MH

MH — Mon, 04 Mar 2013 04:11:54 +0000

@Mohammad
U need 7 bits i.e. 2^7 = 128 Sub-Nets therefore Mask will be 255.254.0.0.

By: Mohamed

Mohamed — Sun, 03 Mar 2013 09:36:03 +0000

Hi All,

Can anyone help me to do a Subnet a 100 Subnets?

IP address is 150.X.x.x can we subnet into 100 networks? Thanks in advance…

By: shshoor

shshoor — Fri, 01 Mar 2013 23:28:24 +0000

que 6 was in the exam today

By: Jah Rastafarai

Jah Rastafarai — Wed, 27 Feb 2013 22:28:12 +0000

Passed CCNA, question 6 from here.

By: hussain

hussain — Mon, 25 Feb 2013 21:05:18 +0000

kindly give me some web site for sub netting practice