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<title>Comments on: CCNA – Subnetting Questions 4</title>
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<item>
<title>By: subnetting</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-2668544</link>
<dc:creator><![CDATA[subnetting]]></dc:creator>
<pubDate>Tue, 31 Mar 2015 04:44:11 +0000</pubDate>
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<description><![CDATA[from 192.10.20.0/24 come up with four subnets]]></description>
<content:encoded><![CDATA[<p>from 192.10.20.0/24 come up with four subnets</p>
]]></content:encoded>
</item>
<item>
<title>By: Anonymous</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-2668538</link>
<dc:creator><![CDATA[Anonymous]]></dc:creator>
<pubDate>Tue, 31 Mar 2015 04:40:39 +0000</pubDate>
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<description><![CDATA[from 192.10.20.0/24 come up with four subnets]]></description>
<content:encoded><![CDATA[<p>from 192.10.20.0/24 come up with four subnets</p>
]]></content:encoded>
</item>
<item>
<title>By: paboy</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-743498</link>
<dc:creator><![CDATA[paboy]]></dc:creator>
<pubDate>Sun, 29 Dec 2013 13:06:56 +0000</pubDate>
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<description><![CDATA[113 point-to-point links. We all know point-to-point links uses a /30. Therefore, 113 point-to-point links is = 113 /30s. We also know in a /30 we have 4 as the step size. Therefore, in 113 /30s we have 4*113 = 452 hosts. Now we need to find the number of host bits to help us get the subnet mask. Remember the formula 2^y-2. 452=2^y-2.......454=2^y. therefore y is 9 host bits. Remember for hosts we always start counting from the right = N.N.11111110.00000000/23.]]></description>
<content:encoded><![CDATA[<p>113 point-to-point links. We all know point-to-point links uses a /30. Therefore, 113 point-to-point links is = 113 /30s. We also know in a /30 we have 4 as the step size. Therefore, in 113 /30s we have 4*113 = 452 hosts. Now we need to find the number of host bits to help us get the subnet mask. Remember the formula 2^y-2. 452=2^y-2…….454=2^y. therefore y is 9 host bits. Remember for hosts we always start counting from the right = N.N.11111110.00000000/23.</p>
]]></content:encoded>
</item>
<item>
<title>By: Anonymous</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-575583</link>
<dc:creator><![CDATA[Anonymous]]></dc:creator>
<pubDate>Tue, 22 Oct 2013 12:45:52 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-575583</guid>
<description><![CDATA[hi friend this is network address we cant assign it to any host .for this subnet 1st valid ip is .25.last valid .30.31 is brodcast this ip also we cant assign to any host.next subnet is .32.if u hav any query email on..jadhavyogesh150@gmail.com]]></description>
<content:encoded><![CDATA[<p>hi friend this is network address we cant assign it to any host .for this subnet 1st valid ip is .25.last valid .30.31 is brodcast this ip also we cant assign to any host.next subnet is .32.if u hav any query email <a href="mailto:on..jadhavyogesh150@gmail.com">on..jadhavyogesh150@gmail.com</a></p>
]]></content:encoded>
</item>
<item>
<title>By: romina</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-503165</link>
<dc:creator><![CDATA[romina]]></dc:creator>
<pubDate>Wed, 02 Oct 2013 06:03:03 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-503165</guid>
<description><![CDATA[would u please some body explain me the Q.10?]]></description>
<content:encoded><![CDATA[<p>would u please some body explain me the Q.10?</p>
]]></content:encoded>
</item>
<item>
<title>By: Mahad</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-475178</link>
<dc:creator><![CDATA[Mahad]]></dc:creator>
<pubDate>Thu, 26 Sep 2013 18:38:29 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-475178</guid>
<description><![CDATA[Thanks to Allah and 9tut, I just passed my exam, good luck everyone. I suggest everyone to go thru all the links on this site, close to 50% of question are found here.]]></description>
<content:encoded><![CDATA[<p>Thanks to Allah and 9tut, I just passed my exam, good luck everyone. I suggest everyone to go thru all the links on this site, close to 50% of question are found here.</p>
]]></content:encoded>
</item>
<item>
<title>By: Anh Tran</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-474342</link>
<dc:creator><![CDATA[Anh Tran]]></dc:creator>
<pubDate>Thu, 26 Sep 2013 16:18:05 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-474342</guid>
<description><![CDATA[Question 8: 113 point to point links that mean we will need 226 ip address. 226 Subnet mask will be: 32 - 9 = 23 => D the correct.]]></description>
<content:encoded><![CDATA[<p>Question 8: 113 point to point links that mean we will need 226 ip address. 226 Subnet mask will be: 32 – 9 = 23 => D the correct.</p>
]]></content:encoded>
</item>
<item>
<title>By: lukin</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-461058</link>
<dc:creator><![CDATA[lukin]]></dc:creator>
<pubDate>Tue, 24 Sep 2013 06:10:07 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-461058</guid>
<description><![CDATA[I will speak in spanish
tienes la red 172.16.1.0 to 172.16.13.0
el lugar de bit para 172.16.13.0 es 172.16.00001101.0
tomas los primero 4 bit del tercer octeto y son los que quedaran fijos.
172.16.00000001.0
172.16.00000010.0
172.16.00000011.0
hasta
172.16.00001101.0
255.255.11110000.00000000/20
si pones atencion los primeros 4 bit del 3 octeto no se movieron por lo cual debes de ser /20]]></description>
<content:encoded><![CDATA[<p>I will speak in spanish </p>
<p>tienes la red 172.16.1.0 to 172.16.13.0<br />
el lugar de bit para 172.16.13.0 es 172.16.00001101.0<br />
tomas los primero 4 bit del tercer octeto y son los que quedaran fijos.<br />
172.16.00000001.0<br />
172.16.00000010.0<br />
172.16.00000011.0<br />
hasta<br />
172.16.00001101.0<br />
255.255.11110000.00000000/20<br />
si pones atencion los primeros 4 bit del 3 octeto no se movieron por lo cual debes de ser /20</p>
]]></content:encoded>
</item>
<item>
<title>By: ndane</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-443085</link>
<dc:creator><![CDATA[ndane]]></dc:creator>
<pubDate>Tue, 17 Sep 2013 14:24:22 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-443085</guid>
<description><![CDATA[q3 can someone explain to me please]]></description>
<content:encoded><![CDATA[<p>q3 can someone explain to me please</p>
]]></content:encoded>
</item>
<item>
<title>By: jasostrong</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-424107</link>
<dc:creator><![CDATA[jasostrong]]></dc:creator>
<pubDate>Wed, 11 Sep 2013 13:40:19 +0000</pubDate>
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<description><![CDATA[Thanks 9tut. I made it. I passed my CCNA 200-120 today. The sim is Access-list 1 , Access-list 2 & EIGRP. A lot of new questions like Netflow, Syslog, SNMP, VRRP, and GLBP.]]></description>
<content:encoded><![CDATA[<p>Thanks 9tut. I made it. I passed my CCNA 200-120 today. The sim is Access-list 1 , Access-list 2 & EIGRP. A lot of new questions like Netflow, Syslog, SNMP, VRRP, and GLBP.</p>
]]></content:encoded>
</item>
<item>
<title>By: Adeel</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-379175</link>
<dc:creator><![CDATA[Adeel]]></dc:creator>
<pubDate>Wed, 14 Aug 2013 09:02:34 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-379175</guid>
<description><![CDATA[Hello Guys I hope you will be fine there. I have CCNA (640-802) and CCNA security (640-554) Vouchers on special discount of 58% for World wide, with six months expiry date till you purchase. Each voucher cost 70USD.
Details Required For CCNA Voucher For Discount Processing:
1-Full Name. 1st Name & Last Name (as you want to appear on certificate & documents)
2-Country.
3-City.
4-State.
5-Pin Code (or Area Code)
6-Residential Address (or where you can collect your Certificate or further correspondence
can be received)
7-Date of birth
Add me on Skype through this information which is written below:
Skype Name: rockon660
you can also email me at this email address which is written below:
madeelqaiser@gmail.com
If you have any Questions feel free to contact me.
Thanks,
Best regards,
Adeel]]></description>
<content:encoded><![CDATA[<p>Hello Guys I hope you will be fine there. I have CCNA (640-802) and CCNA security (640-554) Vouchers on special discount of 58% for World wide, with six months expiry date till you purchase. Each voucher cost 70USD.</p>
<p>Details Required For CCNA Voucher For Discount Processing:</p>
<p>1-Full Name. 1st Name & Last Name (as you want to appear on certificate & documents)<br />
2-Country.<br />
3-City.<br />
4-State.<br />
5-Pin Code (or Area Code)<br />
6-Residential Address (or where you can collect your Certificate or further correspondence<br />
can be received)<br />
7-Date of birth<br />
Add me on Skype through this information which is written below:<br />
Skype Name: rockon660<br />
you can also email me at this email address which is written below:<br />
<a href="mailto:madeelqaiser@gmail.com">madeelqaiser@gmail.com</a><br />
If you have any Questions feel free to contact me.</p>
<p>Thanks,<br />
Best regards,<br />
Adeel</p>
]]></content:encoded>
</item>
<item>
<title>By: help!!</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-368220</link>
<dc:creator><![CDATA[help!!]]></dc:creator>
<pubDate>Sun, 04 Aug 2013 11:14:52 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-368220</guid>
<description><![CDATA[@ABP: Use summarized route from phoenix route... hope this helps..]]></description>
<content:encoded><![CDATA[<p>@ABP: Use summarized route from phoenix route… hope this helps..</p>
]]></content:encoded>
</item>
<item>
<title>By: ABP</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-364112</link>
<dc:creator><![CDATA[ABP]]></dc:creator>
<pubDate>Mon, 29 Jul 2013 15:50:17 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-364112</guid>
<description><![CDATA[can any one explain me the question 2]]></description>
<content:encoded><![CDATA[<p>can any one explain me the question 2</p>
]]></content:encoded>
</item>
<item>
<title>By: Bill_Ado</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-358972</link>
<dc:creator><![CDATA[Bill_Ado]]></dc:creator>
<pubDate>Wed, 24 Jul 2013 21:31:27 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-358972</guid>
<description><![CDATA[@Nourhan: host B has a valid IP, from the IP 192.168.1.111, we have this range:
Subnet 192.168.1.96, broadcast 192.168.1.127 and the IP assigned to hosts should be anything in between and we'll have for hosts, the range (192.168.1.97-192.168.1.126), so 192.168.1.111 is a valid host address, i hope it makes sens to you]]></description>
<content:encoded><![CDATA[<p>@Nourhan: host B has a valid IP, from the IP 192.168.1.111, we have this range:<br />
Subnet 192.168.1.96, broadcast 192.168.1.127 and the IP assigned to hosts should be anything in between and we’ll have for hosts, the range (192.168.1.97-192.168.1.126), so 192.168.1.111 is a valid host address, i hope it makes sens to you</p>
]]></content:encoded>
</item>
<item>
<title>By: Vick</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-353207</link>
<dc:creator><![CDATA[Vick]]></dc:creator>
<pubDate>Sun, 21 Jul 2013 18:07:14 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-353207</guid>
<description><![CDATA[freinds please help me i wanna take the CCNA EXAM IN COMING DAYS
please send me last dumps in my email
vickakop@gmail.com
thanks in advance]]></description>
<content:encoded><![CDATA[<p>freinds please help me i wanna take the CCNA EXAM IN COMING DAYS<br />
please send me last dumps in my email<br />
<a href="mailto:vickakop@gmail.com">vickakop@gmail.com</a><br />
thanks in advance</p>
]]></content:encoded>
</item>
<item>
<title>By: Nourhan</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-351056</link>
<dc:creator><![CDATA[Nourhan]]></dc:creator>
<pubDate>Sat, 20 Jul 2013 03:22:13 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-351056</guid>
<description><![CDATA[Q7
host B has broadcast IP also, Am i right ?]]></description>
<content:encoded><![CDATA[<p>Q7</p>
<p>host B has broadcast IP also, Am i right ?</p>
]]></content:encoded>
</item>
<item>
<title>By: RBK</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-348711</link>
<dc:creator><![CDATA[RBK]]></dc:creator>
<pubDate>Tue, 09 Jul 2013 14:35:46 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-348711</guid>
<description><![CDATA[Hey guys The ip addresses are same or not?]]></description>
<content:encoded><![CDATA[<p>Hey guys The ip addresses are same or not?</p>
]]></content:encoded>
</item>
<item>
<title>By: Ariel</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-345431</link>
<dc:creator><![CDATA[Ariel]]></dc:creator>
<pubDate>Wed, 26 Jun 2013 08:15:07 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-345431</guid>
<description><![CDATA[Krishna,
they are on the same network: 192.168.1.32 /27
the range of hosts for this network is 192.168.1.33 - 192.168.1.62]]></description>
<content:encoded><![CDATA[<p>Krishna,<br />
they are on the same network: 192.168.1.32 /27<br />
the range of hosts for this network is 192.168.1.33 – 192.168.1.62</p>
]]></content:encoded>
</item>
<item>
<title>By: feroz</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-343689</link>
<dc:creator><![CDATA[feroz]]></dc:creator>
<pubDate>Wed, 19 Jun 2013 12:36:22 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-343689</guid>
<description><![CDATA[@bam Thanks for great explanation.]]></description>
<content:encoded><![CDATA[<p>@bam Thanks for great explanation.</p>
]]></content:encoded>
</item>
<item>
<title>By: Krishna</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-343334</link>
<dc:creator><![CDATA[Krishna]]></dc:creator>
<pubDate>Tue, 18 Jun 2013 02:34:10 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-343334</guid>
<description><![CDATA[For question 7, option A is valid too.....HostA is not on the same subnet as its default gateway.
Why is that?]]></description>
<content:encoded><![CDATA[<p>For question 7, option A is valid too…..HostA is not on the same subnet as its default gateway.</p>
<p>Why is that?</p>
]]></content:encoded>
</item>
<item>
<title>By: bam</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-342571</link>
<dc:creator><![CDATA[bam]]></dc:creator>
<pubDate>Fri, 14 Jun 2013 17:18:39 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-342571</guid>
<description><![CDATA[@ Tin for question number 8, use shortcut the question ask 113 point to point links you can only use here is /30 in a point to point links wich 252 (includes = 1 network address, 2 usable ips and 1 broadcast adress) the total is 4. now 113 * 4 = 452 you need 452 ips. what address can support 452 ips? 1111111.1111111.11111110.00000000 = 2e9 = 512. 512 is enough right? so how many bits are there? /23. so the answer is (255.255.254.0 and 255.255.255.252) or (/23 and /30) which is D.
I hope you get my point sorry my english is bad.]]></description>
<content:encoded><![CDATA[<p>@ Tin for question number 8, use shortcut the question ask 113 point to point links you can only use here is /30 in a point to point links wich 252 (includes = 1 network address, 2 usable ips and 1 broadcast adress) the total is 4. now 113 * 4 = 452 you need 452 ips. what address can support 452 ips? 1111111.1111111.11111110.00000000 = 2e9 = 512. 512 is enough right? so how many bits are there? /23. so the answer is (255.255.254.0 and 255.255.255.252) or (/23 and /30) which is D. </p>
<p>I hope you get my point sorry my english is bad.</p>
]]></content:encoded>
</item>
<item>
<title>By: Tin</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-334942</link>
<dc:creator><![CDATA[Tin]]></dc:creator>
<pubDate>Sat, 08 Jun 2013 19:04:37 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-334942</guid>
<description><![CDATA[I mean Q8. Not Q10]]></description>
<content:encoded><![CDATA[<p>I mean Q8. Not Q10</p>
]]></content:encoded>
</item>
<item>
<title>By: Tin</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-334940</link>
<dc:creator><![CDATA[Tin]]></dc:creator>
<pubDate>Sat, 08 Jun 2013 19:03:40 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-334940</guid>
<description><![CDATA[Can someone please explain Q10? Thanks in advance.]]></description>
<content:encoded><![CDATA[<p>Can someone please explain Q10? Thanks in advance.</p>
]]></content:encoded>
</item>
<item>
<title>By: David Okeri</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-322351</link>
<dc:creator><![CDATA[David Okeri]]></dc:creator>
<pubDate>Wed, 05 Jun 2013 10:21:22 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-322351</guid>
<description><![CDATA[Pliz i will sit for the CCNA exam next month, can someone send me the latest dumps on email: olesimbe@yahoo.com]]></description>
<content:encoded><![CDATA[<p>Pliz i will sit for the CCNA exam next month, can someone send me the latest dumps on email: <a href="mailto:olesimbe@yahoo.com">olesimbe@yahoo.com</a></p>
]]></content:encoded>
</item>
<item>
<title>By: Richard</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-305302</link>
<dc:creator><![CDATA[Richard]]></dc:creator>
<pubDate>Wed, 15 May 2013 04:37:10 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-305302</guid>
<description><![CDATA[Kurt,
what do you mean by gateway address? there is no router there yet configured. it only talks subnetting and the number of hosts needed.
Gateway address should be on the same subnet of your hosts.]]></description>
<content:encoded><![CDATA[<p>Kurt,<br />
what do you mean by gateway address? there is no router there yet configured. it only talks subnetting and the number of hosts needed.<br />
Gateway address should be on the same subnet of your hosts.</p>
]]></content:encoded>
</item>
<item>
<title>By: Kurt</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-304870</link>
<dc:creator><![CDATA[Kurt]]></dc:creator>
<pubDate>Fri, 10 May 2013 10:26:22 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-304870</guid>
<description><![CDATA[Q1 Don't you think the gateway address of each subnet should be considered?]]></description>
<content:encoded><![CDATA[<p>Q1 Don’t you think the gateway address of each subnet should be considered?</p>
]]></content:encoded>
</item>
<item>
<title>By: Big Dr.</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-302201</link>
<dc:creator><![CDATA[Big Dr.]]></dc:creator>
<pubDate>Sat, 20 Apr 2013 22:56:03 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-302201</guid>
<description><![CDATA[Q7 WAS ON MY EXAM TODAY]]></description>
<content:encoded><![CDATA[<p>Q7 WAS ON MY EXAM TODAY</p>
]]></content:encoded>
</item>
<item>
<title>By: Bhargav</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-301680</link>
<dc:creator><![CDATA[Bhargav]]></dc:creator>
<pubDate>Wed, 17 Apr 2013 17:03:12 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-301680</guid>
<description><![CDATA[any body wants ccna online training and have any doubts regarding concepts contact me bhargav.cisco@gmail.com]]></description>
<content:encoded><![CDATA[<p>any body wants ccna online training and have any doubts regarding concepts contact me <a href="mailto:bhargav.cisco@gmail.com">bhargav.cisco@gmail.com</a></p>
]]></content:encoded>
</item>
<item>
<title>By: Ashique</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-299979</link>
<dc:creator><![CDATA[Ashique]]></dc:creator>
<pubDate>Mon, 08 Apr 2013 22:04:28 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-299979</guid>
<description><![CDATA[For Question-8
First, consider host address. You need fewest host address, so for point-to-point links, it should be 4 (1 network address, 1 broadcast address & 2 link address) and it take 2 bits. Then you consider subnet address. 113 takes 7 bits. So host & subnet takes 2+7=9 bits. So our initial network should be 32 – 9 = 23]]></description>
<content:encoded><![CDATA[<p>For Question-8<br />
First, consider host address. You need fewest host address, so for point-to-point links, it should be 4 (1 network address, 1 broadcast address & 2 link address) and it take 2 bits. Then you consider subnet address. 113 takes 7 bits. So host & subnet takes 2+7=9 bits. So our initial network should be 32 – 9 = 23</p>
]]></content:encoded>
</item>
<item>
<title>By: ALI</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-299568</link>
<dc:creator><![CDATA[ALI]]></dc:creator>
<pubDate>Fri, 05 Apr 2013 15:07:11 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-299568</guid>
<description><![CDATA[ques-8
i am thinking same as you , please explain if any one think different .
kind regards]]></description>
<content:encoded><![CDATA[<p>ques-8<br />
i am thinking same as you , please explain if any one think different .<br />
kind regards</p>
]]></content:encoded>
</item>
<item>
<title>By: here to help</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-296548</link>
<dc:creator><![CDATA[here to help]]></dc:creator>
<pubDate>Sun, 17 Mar 2013 06:04:37 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-296548</guid>
<description><![CDATA[/26 gives 64 hosts (including the network and broadcast)
/20 gives 4096 hosts (including the network and broadcast)
4096/ 64 = 64 (networks)
that's what i think is the answer for the first part of the question.]]></description>
<content:encoded><![CDATA[<p>/26 gives 64 hosts (including the network and broadcast)<br />
/20 gives 4096 hosts (including the network and broadcast)<br />
4096/ 64 = 64 (networks)<br />
that’s what i think is the answer for the first part of the question.</p>
]]></content:encoded>
</item>
<item>
<title>By: Need Help!</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-296505</link>
<dc:creator><![CDATA[Need Help!]]></dc:creator>
<pubDate>Sat, 16 Mar 2013 20:52:51 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-296505</guid>
<description><![CDATA[My teach ask us to solve this question:
How many /26 aligned networks can be aggregated together to give a /20 contiguous network. What class is the network obtained in this way?
/26 gives us 32 ip that would be 6 subnets
/20 give us 16 ip that would be 12 subnets
thats as far as i got. can anyone help]]></description>
<content:encoded><![CDATA[<p>My teach ask us to solve this question:</p>
<p>How many /26 aligned networks can be aggregated together to give a /20 contiguous network. What class is the network obtained in this way?</p>
<p>/26 gives us 32 ip that would be 6 subnets<br />
/20 give us 16 ip that would be 12 subnets</p>
<p>thats as far as i got. can anyone help</p>
]]></content:encoded>
</item>
<item>
<title>By: jay</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-4#comment-295909</link>
<dc:creator><![CDATA[jay]]></dc:creator>
<pubDate>Wed, 13 Mar 2013 14:01:33 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-295909</guid>
<description><![CDATA[have to consider for number of hosts too. Point-to-point links have 2 hosts.
h=2= (2^y) - 2 thus, y =2.
2 zero bits are borrowed, followed by 7 1's]]></description>
<content:encoded><![CDATA[<p>have to consider for number of hosts too. Point-to-point links have 2 hosts. </p>
<p>h=2= (2^y) – 2 thus, y =2. </p>
<p>2 zero bits are borrowed, followed by 7 1′s</p>
]]></content:encoded>
</item>
<item>
<title>By: ques-8</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-295754</link>
<dc:creator><![CDATA[ques-8]]></dc:creator>
<pubDate>Tue, 12 Mar 2013 19:04:42 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-295754</guid>
<description><![CDATA[Q8..!!
Answer should be B (/25) Coz 7 bit will be off then and 2^7=128>113
Please Explain]]></description>
<content:encoded><![CDATA[<p>Q8..!!<br />
Answer should be B (/25) Coz 7 bit will be off then and 2^7=128>113</p>
<p>Please Explain</p>
]]></content:encoded>
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<item>
<title>By: faaAdo</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-295752</link>
<dc:creator><![CDATA[faaAdo]]></dc:creator>
<pubDate>Tue, 12 Mar 2013 18:36:49 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-295752</guid>
<description><![CDATA[Q-4..!!
Sorry i got it, they are asking "which subnet", 56 isn't the subnet so the only option left is 64]]></description>
<content:encoded><![CDATA[<p>Q-4..!!<br />
Sorry i got it, they are asking “which subnet”, 56 isn’t the subnet so the only option left is 64</p>
]]></content:encoded>
</item>
<item>
<title>By: faaAdo</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-295751</link>
<dc:creator><![CDATA[faaAdo]]></dc:creator>
<pubDate>Tue, 12 Mar 2013 18:29:44 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-295751</guid>
<description><![CDATA[Q-4
Why not Option-D...???]]></description>
<content:encoded><![CDATA[<p>Q-4<br />
Why not Option-D…???</p>
]]></content:encoded>
</item>
<item>
<title>By: shshoor</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-293451</link>
<dc:creator><![CDATA[shshoor]]></dc:creator>
<pubDate>Fri, 01 Mar 2013 23:29:46 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-293451</guid>
<description><![CDATA[ques 8 was in the exam today]]></description>
<content:encoded><![CDATA[<p>ques 8 was in the exam today</p>
]]></content:encoded>
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<item>
<title>By: Jah Rastafarai</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-292964</link>
<dc:creator><![CDATA[Jah Rastafarai]]></dc:creator>
<pubDate>Wed, 27 Feb 2013 22:29:45 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-292964</guid>
<description><![CDATA[Passed CCNA, question 8 from here.]]></description>
<content:encoded><![CDATA[<p>Passed CCNA, question 8 from here.</p>
]]></content:encoded>
</item>
<item>
<title>By: Rooki3</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-286442</link>
<dc:creator><![CDATA[Rooki3]]></dc:creator>
<pubDate>Thu, 31 Jan 2013 14:49:26 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-286442</guid>
<description><![CDATA[Valid Que :D
Q:7]]></description>
<content:encoded><![CDATA[<p>Valid Que :D</p>
<p>Q:7</p>
]]></content:encoded>
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<item>
<title>By: route summarization</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-286158</link>
<dc:creator><![CDATA[route summarization]]></dc:creator>
<pubDate>Wed, 30 Jan 2013 20:47:48 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-286158</guid>
<description><![CDATA[@9tut: do we have a route summarization topic here? thanks]]></description>
<content:encoded><![CDATA[<p>@9tut: do we have a route summarization topic here? thanks</p>
]]></content:encoded>
</item>
<item>
<title>By: Nana</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-286152</link>
<dc:creator><![CDATA[Nana]]></dc:creator>
<pubDate>Wed, 30 Jan 2013 20:04:12 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-286152</guid>
<description><![CDATA[Guys help me with an activation code for visual certexam manager.i cant access vce files.Even the trial version seems fake.]]></description>
<content:encoded><![CDATA[<p>Guys help me with an activation code for visual certexam manager.i cant access vce files.Even the trial version seems fake.</p>
]]></content:encoded>
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<item>
<title>By: dato pantsulaia</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-285242</link>
<dc:creator><![CDATA[dato pantsulaia]]></dc:creator>
<pubDate>Sun, 27 Jan 2013 13:33:46 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-285242</guid>
<description><![CDATA[MalikCCNA
three web server need to have three valid ip address on the same sabnet or the last three bits in last octet
00000000.00000000.00000000.00000/000 for that the mask will be
11111111.11111111.11111111.11111 000 or 255.255.255.248]]></description>
<content:encoded><![CDATA[<p>MalikCCNA<br />
three web server need to have three valid ip address on the same sabnet or the last three bits in last octet<br />
00000000.00000000.00000000.00000/000 for that the mask will be<br />
11111111.11111111.11111111.11111 000 or 255.255.255.248</p>
]]></content:encoded>
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<item>
<title>By: tamil</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-281061</link>
<dc:creator><![CDATA[tamil]]></dc:creator>
<pubDate>Fri, 18 Jan 2013 04:51:14 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-281061</guid>
<description><![CDATA[please help me..why we should give same set of network ip address to serial link
this is my email tamilarasiek@gmail.com]]></description>
<content:encoded><![CDATA[<p>please help me..why we should give same set of network ip address to serial link<br />
this is my email <a href="mailto:tamilarasiek@gmail.com">tamilarasiek@gmail.com</a></p>
]]></content:encoded>
</item>
<item>
<title>By: TDy11</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-259369</link>
<dc:creator><![CDATA[TDy11]]></dc:creator>
<pubDate>Thu, 13 Dec 2012 20:14:02 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-259369</guid>
<description><![CDATA[TY 9tut.
Today I have passed the CCNA. (860/825)
50 questions 3 labs (VTP, EIGRP, ACL). 35 from 9tut.
Also thanks a lot Brar and Sekhar (still valid from examcollection)
Ty again 9tut
from here none]]></description>
<content:encoded><![CDATA[<p>TY 9tut. </p>
<p>Today I have passed the CCNA. (860/825)<br />
50 questions 3 labs (VTP, EIGRP, ACL). 35 from 9tut.</p>
<p>Also thanks a lot Brar and Sekhar (still valid from examcollection)</p>
<p>Ty again 9tut</p>
<p>from here none</p>
]]></content:encoded>
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<item>
<title>By: James</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-258039</link>
<dc:creator><![CDATA[James]]></dc:creator>
<pubDate>Wed, 12 Dec 2012 00:49:24 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-258039</guid>
<description><![CDATA["i dont get why B is correct, E makes more sense to me since you are subnetting from a Class A address."
It's not the correct answer is D
Look at it this way:
A. 10.10.0.0/18 - Useable range 10.10.192.0 - 10.10.255.255 (around 7936 ip addresses) subnetted with /30 (1984 blocks of 4 addresses)
B. 10.10.0.0/25 - Useable range 10.10.0.128 - 10.10.0.255 (128 addresses) subnetted with /30 (32 blocks of 4 addresses)
B. 10.10.0.0/24 - Useable range 10.10.0.0 - 10.10.0.255 (256 addresses) subnetted with /30 (64 blocks of 4 addresses)
D. 10.10.0.0/23 - Useable range 10.10.0.0 - 10.10.1.255 (around 512 ip addresses) subnetted with /30 (128 blocks of 4 addresses)
E. 10.10.0.0/16 - Useable range 10.10.0.0 - 10.10.255.255 (65,280 ip addresses) subnetted with /30 (16,230 blocks of 4 addresses)
Since you only have a requirement of 113 WAN Links of four addresses each (network, host, host, broadcast)....some under fill the requirements and some are overkill.]]></description>
<content:encoded><![CDATA[<p>“i dont get why B is correct, E makes more sense to me since you are subnetting from a Class A address.”</p>
<p>It’s not the correct answer is D</p>
<p>Look at it this way:<br />
A. 10.10.0.0/18 – Useable range 10.10.192.0 – 10.10.255.255 (around 7936 ip addresses) subnetted with /30 (1984 blocks of 4 addresses)</p>
<p>B. 10.10.0.0/25 – Useable range 10.10.0.128 – 10.10.0.255 (128 addresses) subnetted with /30 (32 blocks of 4 addresses)</p>
<p>B. 10.10.0.0/24 – Useable range 10.10.0.0 – 10.10.0.255 (256 addresses) subnetted with /30 (64 blocks of 4 addresses) </p>
<p>D. 10.10.0.0/23 – Useable range 10.10.0.0 – 10.10.1.255 (around 512 ip addresses) subnetted with /30 (128 blocks of 4 addresses) </p>
<p>E. 10.10.0.0/16 – Useable range 10.10.0.0 – 10.10.255.255 (65,280 ip addresses) subnetted with /30 (16,230 blocks of 4 addresses) </p>
<p>Since you only have a requirement of 113 WAN Links of four addresses each (network, host, host, broadcast)….some under fill the requirements and some are overkill.</p>
]]></content:encoded>
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<item>
<title>By: sally</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-255786</link>
<dc:creator><![CDATA[sally]]></dc:creator>
<pubDate>Sat, 08 Dec 2012 14:11:23 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-255786</guid>
<description><![CDATA[Can somebody plz explain this question...
The network administrator is asked to configure 113 point-to-point links. Which IP addressing scheme best defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses
A. 10.10.0.0/18 subnetted with mask 255.255.255.252
B. 10.10.0.0/25 subnetted with mask 255.255.255.252
C. 10.10.0.0/24 subnetted with mask 255.255.255.252
D. 10.10.0.0/23 subnetted with mask 255.255.255.252
E. 10.10.0.0/16 subnetted with mask 255.255.255.252
i dont get why B is correct, E makes more sense to me since you are subnetting from a Class A address.]]></description>
<content:encoded><![CDATA[<p>Can somebody plz explain this question…</p>
<p>The network administrator is asked to configure 113 point-to-point links. Which IP addressing scheme best defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses</p>
<p>A. 10.10.0.0/18 subnetted with mask 255.255.255.252<br />
B. 10.10.0.0/25 subnetted with mask 255.255.255.252<br />
C. 10.10.0.0/24 subnetted with mask 255.255.255.252<br />
D. 10.10.0.0/23 subnetted with mask 255.255.255.252<br />
E. 10.10.0.0/16 subnetted with mask 255.255.255.252</p>
<p>i dont get why B is correct, E makes more sense to me since you are subnetting from a Class A address.</p>
]]></content:encoded>
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<item>
<title>By: sally</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-255785</link>
<dc:creator><![CDATA[sally]]></dc:creator>
<pubDate>Sat, 08 Dec 2012 14:10:23 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-255785</guid>
<description><![CDATA[Can somebody plz explain this question...
The network administrator is asked to configure 113 point-to-point links. Which IP addressing scheme best defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses
A. 10.10.0.018 subnetted with mask 255.255.255.252
B. 10.10.0.025 subnetted with mask 255.255.255.252
C. 10.10.0.024 subnetted with mask 255.255.255.252
D. 10.10.0.023 subnetted with mask 255.255.255.252
E. 10.10.0.016 subnetted with mask 255.255.255.252
i dont get why B is correct, E makes more sense to me since you are subnetting from a Class A address.]]></description>
<content:encoded><![CDATA[<p>Can somebody plz explain this question…</p>
<p>The network administrator is asked to configure 113 point-to-point links. Which IP addressing scheme best defines the address range and subnet mask that meet the requirement and waste the fewest subnet and host addresses</p>
<p>A. 10.10.0.018 subnetted with mask 255.255.255.252<br />
B. 10.10.0.025 subnetted with mask 255.255.255.252<br />
C. 10.10.0.024 subnetted with mask 255.255.255.252<br />
D. 10.10.0.023 subnetted with mask 255.255.255.252<br />
E. 10.10.0.016 subnetted with mask 255.255.255.252</p>
<p>i dont get why B is correct, E makes more sense to me since you are subnetting from a Class A address.</p>
]]></content:encoded>
</item>
<item>
<title>By: eddy</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-250147</link>
<dc:creator><![CDATA[eddy]]></dc:creator>
<pubDate>Wed, 28 Nov 2012 06:48:14 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-250147</guid>
<description><![CDATA[hi
ref Q1
Each subnet has 30 hosts /27
should this not be 6 bits? i thought that 30 hosts would = 30+2 (32) which would be 6 bits
any help?]]></description>
<content:encoded><![CDATA[<p>hi<br />
ref Q1<br />
Each subnet has 30 hosts /27<br />
should this not be 6 bits? i thought that 30 hosts would = 30+2 (32) which would be 6 bits<br />
any help?</p>
]]></content:encoded>
</item>
<item>
<title>By: rusure</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-248318</link>
<dc:creator><![CDATA[rusure]]></dc:creator>
<pubDate>Wed, 21 Nov 2012 02:14:12 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-248318</guid>
<description><![CDATA[the third statement is "acces-list 100 permit ip any any"]]></description>
<content:encoded><![CDATA[<p>the third statement is “acces-list 100 permit ip any any”</p>
]]></content:encoded>
</item>
<item>
<title>By: rusure</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-248315</link>
<dc:creator><![CDATA[rusure]]></dc:creator>
<pubDate>Wed, 21 Nov 2012 01:52:16 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-248315</guid>
<description><![CDATA[In the ACL examples there is one that says
"permit host B from accessing the finance server.."
"deny host B from accessing the OTHER server not the whole network"
Shouldn't the first request above say DENY host B from accessing the finance server?
Usually you deny something FROM and permit something TO.
Besides that ... permitting it to the server useless as the other hosts also have permission
from the third statement.]]></description>
<content:encoded><![CDATA[<p>In the ACL examples there is one that says<br />
“permit host B from accessing the finance server..”<br />
“deny host B from accessing the OTHER server not the whole network”</p>
<p>Shouldn’t the first request above say DENY host B from accessing the finance server?<br />
Usually you deny something FROM and permit something TO.<br />
Besides that … permitting it to the server useless as the other hosts also have permission<br />
from the third statement.</p>
]]></content:encoded>
</item>
<item>
<title>By: Godjilaye</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-247882</link>
<dc:creator><![CDATA[Godjilaye]]></dc:creator>
<pubDate>Sun, 18 Nov 2012 20:48:59 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-247882</guid>
<description><![CDATA[Hallo
Plz can someone explain to me why on question 4 answer B is right? and why not D.
thanks]]></description>
<content:encoded><![CDATA[<p>Hallo</p>
<p>Plz can someone explain to me why on question 4 answer B is right? and why not D.</p>
<p>thanks</p>
]]></content:encoded>
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<item>
<title>By: Imran</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-247829</link>
<dc:creator><![CDATA[Imran]]></dc:creator>
<pubDate>Sun, 18 Nov 2012 15:37:05 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-247829</guid>
<description><![CDATA[Hi, Please can some one explained Question no. 3]]></description>
<content:encoded><![CDATA[<p>Hi, Please can some one explained Question no. 3</p>
]]></content:encoded>
</item>
<item>
<title>By: Bite</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-241357</link>
<dc:creator><![CDATA[Bite]]></dc:creator>
<pubDate>Fri, 19 Oct 2012 03:18:43 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-241357</guid>
<description><![CDATA[@kai
Which three statements correctly describe Network Device A? (Choose three.)
Here the main Idea is
If they are on the same subnet we need not give the IP address. If they are not then we have to give them
Given two address are 10.1.0.36 and 10.1.1.70
So if we take
A.
With a network wide mask of 255.255.255.128, each interface does not require an IP address.
we can see that if we use this mask they are on different subnet so we need ip, so A is incorrect.
B.
With a network wide mask of 255.255.255.128, each interface does require an IP address on a unique IP subnet.
This is correct as we do require IP addresses
C.
With a network wide mask of 255.255.255.0, must be a Layer 2 device for the PCs to communicate with each other.
NO, we need layer 3 as IP address is involved.
D.
With a network wide mask of 255.255.255.0, must be a Layer 3 device for the PCs to communicate with each other.
YES.
E.
With a network wide mask of 255.255.254.0, each interface does not require an IP address.
Yes, as both are on the same subnet
Thanks]]></description>
<content:encoded><![CDATA[<p>@kai</p>
<p>Which three statements correctly describe Network Device A? (Choose three.)</p>
<p> Here the main Idea is </p>
<p>If they are on the same subnet we need not give the IP address. If they are not then we have to give them</p>
<p>Given two address are 10.1.0.36 and 10.1.1.70</p>
<p>So if we take </p>
<p>A.<br />
With a network wide mask of 255.255.255.128, each interface does not require an IP address.</p>
<p>we can see that if we use this mask they are on different subnet so we need ip, so A is incorrect.<br />
B.<br />
With a network wide mask of 255.255.255.128, each interface does require an IP address on a unique IP subnet.<br />
This is correct as we do require IP addresses </p>
<p>C.<br />
With a network wide mask of 255.255.255.0, must be a Layer 2 device for the PCs to communicate with each other.</p>
<p>NO, we need layer 3 as IP address is involved.</p>
<p>D.<br />
With a network wide mask of 255.255.255.0, must be a Layer 3 device for the PCs to communicate with each other.<br />
YES.<br />
E.<br />
With a network wide mask of 255.255.254.0, each interface does not require an IP address.<br />
Yes, as both are on the same subnet</p>
<p>Thanks</p>
]]></content:encoded>
</item>
<item>
<title>By: Bite</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-241356</link>
<dc:creator><![CDATA[Bite]]></dc:creator>
<pubDate>Fri, 19 Oct 2012 02:59:41 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-241356</guid>
<description><![CDATA[@Q8
Hi All!
This almost wated a lot of time on this so just sharing what I have learnt if this helps!
when we do according to the basics we know we have for 113 links we need is
2*2*2*2*2*2*2=7 bits to be reserved so
we have is some class address where 7 bits have to be reserved.
from the given options below we see them like this
10.10.0.0/23 subnetted with mask 255.255.255.252
so for 255.255.255.252 is nothing but /30 so if we
by increasing given /23 to /30 we have increased address by 30-23=7
which can give 2^7 addresses we need.
say if we take other options we have
10.10.0.0/25 subnetted with mask 255.255.255.252
/25 to /30 we have 30-25=5
2^5=32
but we need 113
Hope this helps
Thanks]]></description>
<content:encoded><![CDATA[<p>@Q8</p>
<p>Hi All!</p>
<p>This almost wated a lot of time on this so just sharing what I have learnt if this helps!</p>
<p>when we do according to the basics we know we have for 113 links we need is</p>
<p>2*2*2*2*2*2*2=7 bits to be reserved so</p>
<p>we have is some class address where 7 bits have to be reserved.</p>
<p>from the given options below we see them like this</p>
<p>10.10.0.0/23 subnetted with mask 255.255.255.252</p>
<p>so for 255.255.255.252 is nothing but /30 so if we </p>
<p>by increasing given /23 to /30 we have increased address by 30-23=7</p>
<p>which can give 2^7 addresses we need.</p>
<p>say if we take other options we have</p>
<p>10.10.0.0/25 subnetted with mask 255.255.255.252</p>
<p>/25 to /30 we have 30-25=5</p>
<p>2^5=32</p>
<p>but we need 113<br />
Hope this helps</p>
<p>Thanks</p>
]]></content:encoded>
</item>
<item>
<title>By: kai</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-233535</link>
<dc:creator><![CDATA[kai]]></dc:creator>
<pubDate>Sun, 09 Sep 2012 02:29:28 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-233535</guid>
<description><![CDATA[can somebody help me with this question please? http://www.aiotestking.com/cisco/2012/04/which-three-statements-correctly-describe-network-device-a/]]></description>
<content:encoded><![CDATA[<p>can somebody help me with this question please? <a href="http://www.aiotestking.com/cisco/2012/04/which-three-statements-correctly-describe-network-device-a/" rel="nofollow">http://www.aiotestking.com/cisco/2012/04/which-three-statements-correctly-describe-network-device-a/</a></p>
]]></content:encoded>
</item>
<item>
<title>By: sniffer</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-233302</link>
<dc:creator><![CDATA[sniffer]]></dc:creator>
<pubDate>Fri, 07 Sep 2012 23:22:51 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-233302</guid>
<description><![CDATA[What is the summarized for these network
172.1.4.0/25
172.1.4.128/25
172.1.5.0/24
172.1.6.0/24
172.1.7.0/24
my answer id 172.1.0.0/21 but in the dump it’s 172.1.0.0/22
@ me and xallax meaning the rite ans is 172.1.4.0/22 not 172.1.0.0/22 as in the dump.
@ me check from ur dump if 172.1.4.0 is part of the ans????]]></description>
<content:encoded><![CDATA[<p>What is the summarized for these network<br />
172.1.4.0/25<br />
172.1.4.128/25<br />
172.1.5.0/24<br />
172.1.6.0/24<br />
172.1.7.0/24</p>
<p>my answer id 172.1.0.0/21 but in the dump it’s 172.1.0.0/22</p>
<p>@ me and xallax meaning the rite ans is 172.1.4.0/22 not 172.1.0.0/22 as in the dump.<br />
@ me check from ur dump if 172.1.4.0 is part of the ans????</p>
]]></content:encoded>
</item>
<item>
<title>By: 9tut</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-233196</link>
<dc:creator><![CDATA[9tut]]></dc:creator>
<pubDate>Fri, 07 Sep 2012 10:53:16 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-233196</guid>
<description><![CDATA[@Tedy_bear: It's my mistake. Thanks for your detection, I fixed it!]]></description>
<content:encoded><![CDATA[<p>@Tedy_bear: It’s my mistake. Thanks for your detection, I fixed it!</p>
]]></content:encoded>
</item>
<item>
<title>By: Tedy_bear</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-233179</link>
<dc:creator><![CDATA[Tedy_bear]]></dc:creator>
<pubDate>Fri, 07 Sep 2012 09:22:37 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-233179</guid>
<description><![CDATA[@9tut Please check for typo - Right Menu URLs showing the same Questions content
http://www.9tut.com/ccna-subnetting-questions-3
http://www.9tut.com/ccna-subnetting-questions-4]]></description>
<content:encoded><![CDATA[<p>@9tut Please check for typo – Right Menu URLs showing the same Questions content<br />
<a href="http://www.9tut.com/ccna-subnetting-questions-3" rel="nofollow">http://www.9tut.com/ccna-subnetting-questions-3</a><br />
<a href="http://www.9tut.com/ccna-subnetting-questions-4" rel="nofollow">http://www.9tut.com/ccna-subnetting-questions-4</a></p>
]]></content:encoded>
</item>
<item>
<title>By: xallax</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-232033</link>
<dc:creator><![CDATA[xallax]]></dc:creator>
<pubDate>Sat, 01 Sep 2012 13:11:23 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-232033</guid>
<description><![CDATA[@malikccna
the smallest subnet to fit 3 servers is the one from option C]]></description>
<content:encoded><![CDATA[<p>@malikccna<br />
the smallest subnet to fit 3 servers is the one from option C</p>
]]></content:encoded>
</item>
<item>
<title>By: MalikCCNA</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-231968</link>
<dc:creator><![CDATA[MalikCCNA]]></dc:creator>
<pubDate>Sat, 01 Sep 2012 05:07:34 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-231968</guid>
<description><![CDATA[You have been asked to come up with a subnet mask that will allow all three web seivers to be on the same network while proving the maximum number of subnets. Which network address and subnet mask meet this requirement?
A.
192.168.252.8 255.255.255.252
B.
192.168.252.16 255.255.255.252
C.
192.168.252.8 255.255.255.248
D.
192.168.252.0 255.255.255.252
E.
192.168.252.16 255.255.255.240
--------------------------------------------
Why the answer is C..?
Can anyone explain please..?]]></description>
<content:encoded><![CDATA[<p>You have been asked to come up with a subnet mask that will allow all three web seivers to be on the same network while proving the maximum number of subnets. Which network address and subnet mask meet this requirement?</p>
<p>A.<br />
192.168.252.8 255.255.255.252</p>
<p>B.<br />
192.168.252.16 255.255.255.252</p>
<p>C.<br />
192.168.252.8 255.255.255.248</p>
<p>D.<br />
192.168.252.0 255.255.255.252</p>
<p>E.<br />
192.168.252.16 255.255.255.240<br />
——————————————–</p>
<p>Why the answer is C..?<br />
Can anyone explain please..?</p>
]]></content:encoded>
</item>
<item>
<title>By: jacsatx</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-231619</link>
<dc:creator><![CDATA[jacsatx]]></dc:creator>
<pubDate>Wed, 29 Aug 2012 21:55:37 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-231619</guid>
<description><![CDATA[no dumps needed on subetting..either u know it or not....907!!..thx 9tut!!]]></description>
<content:encoded><![CDATA[<p>no dumps needed on subetting..either u know it or not….907!!..thx 9tut!!</p>
]]></content:encoded>
</item>
<item>
<title>By: atman</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-231456</link>
<dc:creator><![CDATA[atman]]></dc:creator>
<pubDate>Wed, 29 Aug 2012 03:48:33 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-231456</guid>
<description><![CDATA[Can anyone mail me dumps please? atman.trivedi@hotmail.com Many thanks]]></description>
<content:encoded><![CDATA[<p>Can anyone mail me dumps please? <a href="mailto:atman.trivedi@hotmail.com">atman.trivedi@hotmail.com</a> Many thanks</p>
]]></content:encoded>
</item>
<item>
<title>By: latha</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-227949</link>
<dc:creator><![CDATA[latha]]></dc:creator>
<pubDate>Sun, 12 Aug 2012 08:42:49 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-227949</guid>
<description><![CDATA[than u very much]]></description>
<content:encoded><![CDATA[<p>than u very much</p>
]]></content:encoded>
</item>
<item>
<title>By: khurrum</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-225284</link>
<dc:creator><![CDATA[khurrum]]></dc:creator>
<pubDate>Wed, 01 Aug 2012 13:47:10 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-225284</guid>
<description><![CDATA[hi, could someone please simplify Q3 for me please?]]></description>
<content:encoded><![CDATA[<p>hi, could someone please simplify Q3 for me please?</p>
]]></content:encoded>
</item>
<item>
<title>By: CCNA as of 8/3/12</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-221576</link>
<dc:creator><![CDATA[CCNA as of 8/3/12]]></dc:creator>
<pubDate>Sat, 21 Jul 2012 16:21:53 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-221576</guid>
<description><![CDATA[@ Anonymous
The Network 172.25.0.0 has been divided into 8 equal subnets. Which of the following IP address can be assigned to the hosts in the 3rd subnet if the IP subnet-zero command is configured on the router? Choose 3 correct answers.
1. 172.25.78.243
2. 172.25.98.16
3. 172.25.72.0
4. 172.25.94.255
5. 172.25.96.17
6 172.25.100.16
correct ans according to dump is
1 3 and 4.
If you have 8 equal subnets you are looking at 32 hosts per subnet. Your subnets would be:
172.25.0.x
172.25.32.x
172.25.64.x
172.25.96.x
This question is specifically looking for hosts in the 3rd subnet. So we would be interested in:
172.25.64.1 - 172.25.64.95.254
Therefore, the correct answers given the choices are 1, 3 and 4]]></description>
<content:encoded><![CDATA[<p>@ Anonymous</p>
<p>The Network 172.25.0.0 has been divided into 8 equal subnets. Which of the following IP address can be assigned to the hosts in the 3rd subnet if the IP subnet-zero command is configured on the router? Choose 3 correct answers.<br />
1. 172.25.78.243<br />
2. 172.25.98.16<br />
3. 172.25.72.0<br />
4. 172.25.94.255<br />
5. 172.25.96.17<br />
6 172.25.100.16<br />
correct ans according to dump is<br />
1 3 and 4.</p>
<p>If you have 8 equal subnets you are looking at 32 hosts per subnet. Your subnets would be:</p>
<p>172.25.0.x<br />
172.25.32.x<br />
172.25.64.x<br />
172.25.96.x</p>
<p>This question is specifically looking for hosts in the 3rd subnet. So we would be interested in:</p>
<p>172.25.64.1 – 172.25.64.95.254</p>
<p>Therefore, the correct answers given the choices are 1, 3 and 4</p>
]]></content:encoded>
</item>
<item>
<title>By: Rajan</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-220348</link>
<dc:creator><![CDATA[Rajan]]></dc:creator>
<pubDate>Wed, 18 Jul 2012 05:36:37 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-220348</guid>
<description><![CDATA[I find Wendell Odom's product to be more inivttiue and easier to just jump right in. In my opinion, the design process that goes into designing any network simulation software, is similar to designing a game. Some games require you to learn the controls, before you can really get started, while others are so well thought out that you can well, just jump right in. However, if anyone has any plans to progress beyond the CCNA (eg. CCNP, etc.), I would recommend taking a look at the other two simulators. When I first purchased RouterSim's Network Visualizer, it was still a buggy product and prone to crashes. Even so, it was the only worthwhile game in town, at the time (2004). I never got the opportunity to finish the labs, as I was called to active duty and served over seas for almost two years. RouterSim's Network Visualizer has a particularly strict software license. You only get one, and in order to install it on another machine, you have to send your activation key back to the company (online, via the software itself). Once the license is back with the company, you can then install the software again on another computer, and then activate the product by downloading activation key from them once again. Ever served in the military? Well when you get those orders, you go. There is not a lot of time. You may have a few days to settle any pending business, like saying goodbye to your family and friends, making sure your will is in order, arrange for your bills to be paid, and so on. So transferring a software license wasn't on the top of my list. My software was originally installed on a desktop and I was not about to lug that (and the monitor) with me in my ruck. By the time I came back, the CCNA exam had changed so much that my simulator was, yes outdated. I tried explaining my situation to the nice folks at RouterSim, but I was informed nicely that I can just purchase the upgrade. Remembering my experiences with the software crashes, I declined and signed up to take a CCNA cram class instead. Big mistake. For a newbie, cram courses don't work. Eight days (8 hours a day) of instruction will not teach you the operations of a network and how Routers and Switches come into play so much so that you can pass the CCNA. Much less, get you so familiar with the input commands that you can use on the job. In my class, I had an Egyptian instructor who may be very knowledgeable, but help me if I can understand a darn thing that he was saying. I just couldn't get pass the accent. The school did however, introduced me to Boson's NetSim, a far superior product than my older version of RouterSim's Network Visualizer. Oh yes, if you decide on taking a class, make sure that they give you access to ACTUAL Cisco equipment! They didn't technically lie to me however, the school did have Cisco equipment, but that was a very brief show and tell. We primarily were working with the NetSim software. There are several versions now CCENT, CCNA, CCNP, etc. They also sell videos and mp3 s, besides the simulation software. Cisco seems to be endorsing them, you can find links to Boson from the Cisco website. To briefly describe the product, you basically have a network simulation software package along with a couple of pdf lab manuals (they are compressed and will appear once you've installed the software). I would print out the manuals and follow through the lessons, chapter by chapter. So why do I prefer Wendell Odom's Network Simulator over the others? One, you get 4 licenses. Yes, you can install your product on FOUR separate computers. Two, the price. Wendell Odom's Network Simulator is under $100 (Amazon price, retail is $149). RouterSim's CCNA Network Visualizer is $229.00. And Boson's NetSim for CCNA is $249. And third, the pdf step-by-step lessons on Wendell Odom's Network Simulator pops up as you activate the corresponding lesson simulation. Something that I can really appreciate, as I will be traveling a lot on my new job, and don't want to carry a hard copy lesson book with me, nor scroll through the pages to the lesson I want. Dual monitors would serve you well here. It really is just simpler to use. You are presented with a lesson menu on the right side. A diagram of your network is on the top left, and the command line section (where you type) is below that. Click on the computer icon on your virtual network, and on the command line section you're looking at the CLI interpretation of what you would see if you were logged on to that computer. The same goes for the switches and the routers. Neat. Do bear in mind however, that network simulators are]]></description>
<content:encoded><![CDATA[<p>I find Wendell Odom’s product to be more inivttiue and easier to just jump right in. In my opinion, the design process that goes into designing any network simulation software, is similar to designing a game. Some games require you to learn the controls, before you can really get started, while others are so well thought out that you can well, just jump right in. However, if anyone has any plans to progress beyond the CCNA (eg. CCNP, etc.), I would recommend taking a look at the other two simulators. When I first purchased RouterSim’s Network Visualizer, it was still a buggy product and prone to crashes. Even so, it was the only worthwhile game in town, at the time (2004). I never got the opportunity to finish the labs, as I was called to active duty and served over seas for almost two years. RouterSim’s Network Visualizer has a particularly strict software license. You only get one, and in order to install it on another machine, you have to send your activation key back to the company (online, via the software itself). Once the license is back with the company, you can then install the software again on another computer, and then activate the product by downloading activation key from them once again. Ever served in the military? Well when you get those orders, you go. There is not a lot of time. You may have a few days to settle any pending business, like saying goodbye to your family and friends, making sure your will is in order, arrange for your bills to be paid, and so on. So transferring a software license wasn’t on the top of my list. My software was originally installed on a desktop and I was not about to lug that (and the monitor) with me in my ruck. By the time I came back, the CCNA exam had changed so much that my simulator was, yes outdated. I tried explaining my situation to the nice folks at RouterSim, but I was informed nicely that I can just purchase the upgrade. Remembering my experiences with the software crashes, I declined and signed up to take a CCNA cram class instead. Big mistake. For a newbie, cram courses don’t work. Eight days (8 hours a day) of instruction will not teach you the operations of a network and how Routers and Switches come into play so much so that you can pass the CCNA. Much less, get you so familiar with the input commands that you can use on the job. In my class, I had an Egyptian instructor who may be very knowledgeable, but help me if I can understand a darn thing that he was saying. I just couldn’t get pass the accent. The school did however, introduced me to Boson’s NetSim, a far superior product than my older version of RouterSim’s Network Visualizer. Oh yes, if you decide on taking a class, make sure that they give you access to ACTUAL Cisco equipment! They didn’t technically lie to me however, the school did have Cisco equipment, but that was a very brief show and tell. We primarily were working with the NetSim software. There are several versions now CCENT, CCNA, CCNP, etc. They also sell videos and mp3 s, besides the simulation software. Cisco seems to be endorsing them, you can find links to Boson from the Cisco website. To briefly describe the product, you basically have a network simulation software package along with a couple of pdf lab manuals (they are compressed and will appear once you’ve installed the software). I would print out the manuals and follow through the lessons, chapter by chapter. So why do I prefer Wendell Odom’s Network Simulator over the others? One, you get 4 licenses. Yes, you can install your product on FOUR separate computers. Two, the price. Wendell Odom’s Network Simulator is under $100 (Amazon price, retail is $149). RouterSim’s CCNA Network Visualizer is $229.00. And Boson’s NetSim for CCNA is $249. And third, the pdf step-by-step lessons on Wendell Odom’s Network Simulator pops up as you activate the corresponding lesson simulation. Something that I can really appreciate, as I will be traveling a lot on my new job, and don’t want to carry a hard copy lesson book with me, nor scroll through the pages to the lesson I want. Dual monitors would serve you well here. It really is just simpler to use. You are presented with a lesson menu on the right side. A diagram of your network is on the top left, and the command line section (where you type) is below that. Click on the computer icon on your virtual network, and on the command line section you’re looking at the CLI interpretation of what you would see if you were logged on to that computer. The same goes for the switches and the routers. Neat. Do bear in mind however, that network simulators are</p>
]]></content:encoded>
</item>
<item>
<title>By: singh</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-219731</link>
<dc:creator><![CDATA[singh]]></dc:creator>
<pubDate>Mon, 16 Jul 2012 19:48:25 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-219731</guid>
<description><![CDATA[If they given the mask /27 then the subnet 0,32,64,96-------------so on.The 3rd subnet is 64 and ip add. range between 64 to 95. That by the correct ans is 1 3 and 4. thanks]]></description>
<content:encoded><![CDATA[<p>If they given the mask /27 then the subnet 0,32,64,96————-so on.The 3rd subnet is 64 and ip add. range between 64 to 95. That by the correct ans is 1 3 and 4. thanks</p>
]]></content:encoded>
</item>
<item>
<title>By: Anonymous</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-219592</link>
<dc:creator><![CDATA[Anonymous]]></dc:creator>
<pubDate>Mon, 16 Jul 2012 12:49:47 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-219592</guid>
<description><![CDATA[The Network 172.25.0.0 has been divided into 8 equal subnets. Which of the following IP address can be assigned to the hosts in the 3rd subnet if the IP subnet-zero command is configured on the router? Choose 3 correct answers.
1. 172.25.78.243
2. 172.25.98.16
3. 172.25.72.0
4. 172.25.94.255
5. 172.25.96.17
6 172.25.100.16
correct ans according to dump is
1 3 and 4.
9TUT could anyone explain how this is calculated?
regards,
Rutz]]></description>
<content:encoded><![CDATA[<p>The Network 172.25.0.0 has been divided into 8 equal subnets. Which of the following IP address can be assigned to the hosts in the 3rd subnet if the IP subnet-zero command is configured on the router? Choose 3 correct answers.</p>
<p>1. 172.25.78.243</p>
<p>2. 172.25.98.16</p>
<p>3. 172.25.72.0</p>
<p>4. 172.25.94.255</p>
<p>5. 172.25.96.17</p>
<p>6 172.25.100.16</p>
<p>correct ans according to dump is</p>
<p>1 3 and 4.</p>
<p>9TUT could anyone explain how this is calculated?</p>
<p>regards,<br />
Rutz</p>
]]></content:encoded>
</item>
<item>
<title>By: 9tut</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-219367</link>
<dc:creator><![CDATA[9tut]]></dc:creator>
<pubDate>Sun, 15 Jul 2012 23:14:20 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-219367</guid>
<description><![CDATA[@youngj: Please read my Subnetting tutorial: http://www.9tut.com/subnetting-tutorial]]></description>
<content:encoded><![CDATA[<p>@youngj: Please read my Subnetting tutorial: <a href="http://www.9tut.com/subnetting-tutorial" rel="nofollow">http://www.9tut.com/subnetting-tutorial</a></p>
]]></content:encoded>
</item>
<item>
<title>By: youngj</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-219313</link>
<dc:creator><![CDATA[youngj]]></dc:creator>
<pubDate>Sun, 15 Jul 2012 18:53:14 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-219313</guid>
<description><![CDATA[this subnetting is really confusing becuz everyone does it their way..........hmmmmmm i am writing my test at the end of this month ......any good help regarding subnetting ,vlsm and summarization questions ???????????i wanna get them done easily ...wts the best way /// plz help]]></description>
<content:encoded><![CDATA[<p>this subnetting is really confusing becuz everyone does it their way……….hmmmmmm i am writing my test at the end of this month ……any good help regarding subnetting ,vlsm and summarization questions ???????????i wanna get them done easily …wts the best way /// plz help</p>
]]></content:encoded>
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<item>
<title>By: dinky</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-218000</link>
<dc:creator><![CDATA[dinky]]></dc:creator>
<pubDate>Thu, 12 Jul 2012 09:17:27 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-218000</guid>
<description><![CDATA[hi sumit..
if you calculate the range or block size it will come out to be 64 and there will be 4 subnets in this case. well first subnet is 192.168.1.0 and second is 192.168.1.64
first three networks in the diagram are from first range so it has to be from 192.168.1.64/26
hope u got it.]]></description>
<content:encoded><![CDATA[<p>hi sumit..</p>
<p>if you calculate the range or block size it will come out to be 64 and there will be 4 subnets in this case. well first subnet is 192.168.1.0 and second is 192.168.1.64<br />
first three networks in the diagram are from first range so it has to be from 192.168.1.64/26</p>
<p>hope u got it.</p>
]]></content:encoded>
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<item>
<title>By: Sumit</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-217952</link>
<dc:creator><![CDATA[Sumit]]></dc:creator>
<pubDate>Thu, 12 Jul 2012 07:46:01 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-217952</guid>
<description><![CDATA[hello,
i got a problem with Q4. i want to know how option B is the correct answer when option D is also with /26 ?]]></description>
<content:encoded><![CDATA[<p>hello,<br />
i got a problem with Q4. i want to know how option B is the correct answer when option D is also with /26 ?</p>
]]></content:encoded>
</item>
<item>
<title>By: dinky</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-216299</link>
<dc:creator><![CDATA[dinky]]></dc:creator>
<pubDate>Sun, 08 Jul 2012 13:42:55 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-216299</guid>
<description><![CDATA[Hello all,
I got a prob with que no 2. Please brief me how we move 2 bits to left from 24 to 22?
Thanks]]></description>
<content:encoded><![CDATA[<p>Hello all,</p>
<p>I got a prob with que no 2. Please brief me how we move 2 bits to left from 24 to 22?</p>
<p>Thanks</p>
]]></content:encoded>
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<item>
<title>By: Chris</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-215407</link>
<dc:creator><![CDATA[Chris]]></dc:creator>
<pubDate>Fri, 06 Jul 2012 13:10:43 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-215407</guid>
<description><![CDATA[Q8,
I found out how it is answer D. What you have to do is look at the subnet mask and which is /30 and then to find the difference between each of the networks which gives you:
A - 12
B - 5
C - 6
D - 7
E - 14
So you then work out how many of subnets for this number of bits, 7 bits gives you 128 which is the best fit for the requirement in the question of 113 networks, with 2 hosts each (point-to-point). Hope this makes more sense now.]]></description>
<content:encoded><![CDATA[<p>Q8,</p>
<p>I found out how it is answer D. What you have to do is look at the subnet mask and which is /30 and then to find the difference between each of the networks which gives you:</p>
<p>A – 12<br />
B – 5<br />
C – 6<br />
D – 7<br />
E – 14</p>
<p>So you then work out how many of subnets for this number of bits, 7 bits gives you 128 which is the best fit for the requirement in the question of 113 networks, with 2 hosts each (point-to-point). Hope this makes more sense now.</p>
]]></content:encoded>
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<item>
<title>By: Chris</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-213930</link>
<dc:creator><![CDATA[Chris]]></dc:creator>
<pubDate>Tue, 03 Jul 2012 14:07:57 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-213930</guid>
<description><![CDATA[For Q8 I put answer D, but when I was working it out I made the mistake of counting the subnets as if it was a class B address.
As it is class A then Kurt is right that the amount of subnets will be these huge figures given so the question could be flawed.
Is it that you are discarding the first two octets because 10.10.0.0 appears to be the network ID you are starting with so you mask out the first two octets and count from there 2, 4, 8, 16, 32, 64, 128 which fits in 113 subnets therefore it is /23. You would then have network IDs of 10.10.0.0, 10.10.2.0, 10.10.4.0, 10.10.6.0, etc. ?]]></description>
<content:encoded><![CDATA[<p>For Q8 I put answer D, but when I was working it out I made the mistake of counting the subnets as if it was a class B address. </p>
<p>As it is class A then Kurt is right that the amount of subnets will be these huge figures given so the question could be flawed. </p>
<p>Is it that you are discarding the first two octets because 10.10.0.0 appears to be the network ID you are starting with so you mask out the first two octets and count from there 2, 4, 8, 16, 32, 64, 128 which fits in 113 subnets therefore it is /23. You would then have network IDs of 10.10.0.0, 10.10.2.0, 10.10.4.0, 10.10.6.0, etc. ?</p>
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<item>
<title>By: God's Grace</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-208008</link>
<dc:creator><![CDATA[God's Grace]]></dc:creator>
<pubDate>Thu, 21 Jun 2012 00:29:51 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-208008</guid>
<description><![CDATA[I passed my ccna exam today Praise be to God! Thank you Jesus! and thanks to 9TUT for the tutorials and explanations, great site and thanks to xallax for your explanations to questions and thanks to www.examcollection.com for the dumps. Pls guys lets donate and help to keep this site up!
48 ques for exams including 3 simulation, I had EIGRP, Acesslist2 and VTP. Make sure the practice the simulation, use packet tracer or gns3. Best wishes to all!]]></description>
<content:encoded><![CDATA[<p>I passed my ccna exam today Praise be to God! Thank you Jesus! and thanks to 9TUT for the tutorials and explanations, great site and thanks to xallax for your explanations to questions and thanks to <a href="http://www.examcollection.com" rel="nofollow">http://www.examcollection.com</a> for the dumps. Pls guys lets donate and help to keep this site up!</p>
<p>48 ques for exams including 3 simulation, I had EIGRP, Acesslist2 and VTP. Make sure the practice the simulation, use packet tracer or gns3. Best wishes to all!</p>
]]></content:encoded>
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<item>
<title>By: dougenius</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-207718</link>
<dc:creator><![CDATA[dougenius]]></dc:creator>
<pubDate>Wed, 20 Jun 2012 12:40:59 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-207718</guid>
<description><![CDATA[Yo 9tut gret stuff you layed here man...send latest brain dumps~ dougenius@live.com]]></description>
<content:encoded><![CDATA[<p>Yo 9tut gret stuff you layed here man…send latest brain dumps~ <a href="mailto:dougenius@live.com">dougenius@live.com</a></p>
]]></content:encoded>
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<item>
<title>By: kurt</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-205231</link>
<dc:creator><![CDATA[kurt]]></dc:creator>
<pubDate>Thu, 14 Jun 2012 18:14:38 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-205231</guid>
<description><![CDATA[/15 = 128 131,070 = 131,198
/16 = 256 65,534 = 65,790
/17 = 512 32,766 = 33,278
/18 = 1,024 16,382 = 17,406
I thought /15 -/17 would be better but /18 appears to be the best one. It wastes the least amount of Host & Subnets.
/20 would be the best (4096 + 4094 = 8190)
Please someone point out what I am doing wrong. I think I am correct here.]]></description>
<content:encoded><![CDATA[<p>/15 = 128 131,070 = 131,198<br />
/16 = 256 65,534 = 65,790<br />
/17 = 512 32,766 = 33,278<br />
/18 = 1,024 16,382 = 17,406</p>
<p>I thought /15 -/17 would be better but /18 appears to be the best one. It wastes the least amount of Host & Subnets. </p>
<p>/20 would be the best (4096 + 4094 = 8190)</p>
<p>Please someone point out what I am doing wrong. I think I am correct here.</p>
]]></content:encoded>
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<item>
<title>By: kurt</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-205229</link>
<dc:creator><![CDATA[kurt]]></dc:creator>
<pubDate>Thu, 14 Jun 2012 18:05:22 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-205229</guid>
<description><![CDATA[NOTE: 113 point-to-point links, thus this means subnet addresses, Not Hosts.]]></description>
<content:encoded><![CDATA[<p>NOTE: 113 point-to-point links, thus this means subnet addresses, Not Hosts.</p>
]]></content:encoded>
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<item>
<title>By: kurt</title>
<link>http://www.9tut.com/ccna-subnetting-questions-4/comment-page-3#comment-205226</link>
<dc:creator><![CDATA[kurt]]></dc:creator>
<pubDate>Thu, 14 Jun 2012 18:01:26 +0000</pubDate>
<guid isPermaLink="false">http://www.9tut.com/?p=872#comment-205226</guid>
<description><![CDATA[Q8 is still confusing after reading all of these answers and explanations.
And moncho was using ClassB subnets, these are Class A, not B!
Subnets Hosts Total
A. 10.10.0.0/18 = 1,024 16,382 = 17,406
B. 10.10.0.0/25 = 131,072 126 = 131,198
C. 10.10.0.0/24 = 65,536 254 = 65,790
D. 10.10.0.0/23 = 32,768 510 = 33,278
E. 10.10.0.0/16 = 256 65,534 = 65,790
If you want the least amount of Host & Subnets, then A would be your best bet, but all of these are terrible answers.
Please someone let me know what I am missing here.]]></description>
<content:encoded><![CDATA[<p>Q8 is still confusing after reading all of these answers and explanations. </p>
<p>And moncho was using ClassB subnets, these are Class A, not B! </p>
<p> Subnets Hosts Total<br />
A. 10.10.0.0/18 = 1,024 16,382 = 17,406<br />
B. 10.10.0.0/25 = 131,072 126 = 131,198<br />
C. 10.10.0.0/24 = 65,536 254 = 65,790<br />
D. 10.10.0.0/23 = 32,768 510 = 33,278<br />
E. 10.10.0.0/16 = 256 65,534 = 65,790</p>
<p>If you want the least amount of Host & Subnets, then A would be your best bet, but all of these are terrible answers. </p>
<p>Please someone let me know what I am missing here.</p>
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