CCNA – IP Address Questions
Here you will find answers to IP Address Questions
Question 1
Which IP address can be assigned to an Internet interface?
A. 10.180.48.224
B. 9.255.255.10
C. 192.168.20.223
D. 172.16.200.18
Answer: B
Explanation
The IP address which can be assigned to an Internet interface is a public IP address. Private IP address are found in the following ranges:
* From 10.0.0.0 to 10.255.255.255
* From 172.16.0.0 to 172.31.255.255
* From 192.168.0.0 to 192.168.255.255
Also some special IP addresses (like the local loopback address 127.0.0.1, multicast addresses…) can’t be assigned to an Internet interface.
In this question only answer B doesn’t belong to the range of private IP address -> B is the correct answer.
Question 2
What will happen if a private IP address is assigned to a public interface connected to an ISP?
A. Addresses in a private range will be not routed on the Internet backbone.
B. Only the ISP router will have the capability to access the public network.
C. The NAT process will be used to translate this address in a valid IP address.
D. Several automated methods will be necessary on the private network.
E. A conflict of IP addresses happens, because other public routers can use the same range.
Answer: A
Question 3
When is it necessary to use a public IP address on a routing interface?
A. Connect a router on a local network.
B. Connect a router to another router.
C. Allow distribution of routes between networks.
D. Translate a private IP address.
E. Connect a network to the Internet.
Answer: E
Question 4
When a DHCP server is configured, which two IP addresses should never be assignable to hosts? (Choose two)
A. network or subnetwork IP address
B. broadcast address on the network
C. IP address leased to the LAN
D. IP address used by the interfaces
E. manually assigned address to the clients
F. designated IP address to the DHCP server
Answer: A B
Explanation
Network or subnetwork IP address (for example 11.0.0.0/8 or 13.1.0.0/16) and broadcast address (for example 23.2.1.255/24) should never be assignable to hosts. When try to assign these addresses to hosts, you will receive an error message saying that they can’t be assignable.
Question 6
The network administrator has asked you to check the status of the workstation’s IP stack by pinging the loopback address. Which address would you ping to perform this task?
A. 10.1.1.1
B. 127.0.0.1
C. 192.168.0.1
D. 239.1.1.1
Answer: B
Explanation
The IP address of 127.0.0.1 is the well-known loopback IP address on a computer. When try pinging this address, you are testing if the TCP/IP stack is working or not.
Question 7
Which command is used to see the path taken by packets across an IP network?
A. show ip route
B. show route
C. traceroute
D. trace ip route
Answer: C
Explanation
Notice that “traceroute” is the command used on a Cisco router while the “tracert” is the command used in MSDOS of Windows. They have the same purpose of finding the path that packets use to reach a destination network.
Question 8
Refer to the exhibit. Which value will be configured for Default Gateway of the Local Area Connection?
A. 10.0.0.0
B. 10.0.0.254
C. 192.223.129.0
D. 192.223.129.254
Answer: B
Explanation
The default gateway IP address must be on the same network with the configured host’s IP address and not is the network or broadcast address -> B is correct.
Question 9
Which of the following describe private IP addresses? (Choose two)
A. addresses chosen by a company to communicate with the Internet
B. addresses that cannot be routed through the public Internet
C. addresses that can be routed through the public Internet
D. a scheme to conserve public addresses
E. addresses licensed to enterprises or ISPs by an Internet registry organization
Answer: B D
Question 10
Refer to the exhibit. A network technician is asked to design a small network with redundancy. The exhibit represents this design, with all hosts configured in the same VLAN. What conclusions can be made about this design?
A. The design will function as intended
B. Spanning-tree will need to be used.
C. The router will not accept the addressing scheme.
D. The connection between switches should be a trunk.
E. The router interfaces must be encapsulated with the 802.1Q protocol.
Answer: C
Explanation
Each interface on a router must be in a different network. If two interfaces are in the same network, the router will not accept it and show error when the administrator assigns it.
tnx 9tut
@xallax
Reagrding Q10.
Can you kindly explain this part of the question for me?
“with all host configured in the SAME VLAN”
And yet the answer to Q10 is “The router will not accept the addressing scheme”
Thanks.
@anonymous
we don’t care that much about the VLANs here, just take a look at the router.
you have two interfaces of the same router configured on the same network/subnetwork. the router will say that they overlap and will not allow you to configure them this way.
192.168.1.1 /24
192.168.1.2 /24
they are on the same network of 192.168.1.1 /24
@xallax
Thanks.
Anyway, so when a question is phrase this way, like Q10, what do you look out for?
Secondly, under subnetting 1, Q5, similar to Q10 above. In that question, it gives a little bit more to work with.
Q: Vlan1 172.16.1.126-84 hosts. Vlan2 172.16.1.129-114 hosts.
It makes it much easier to figure out the addressing scheme.
Are these two question in any way much the same? Thanks.
@anonymous
first thing first: i read the question, the exhibit, the possible answers.
then i check the possible answers if i can rule any out.
then i go back to the exhibit, make sure it’s all okay, try to rule out some of the possible answers.
then i go to the question.
for this question the exhibit was the key to answer this correctly
@xallax
Thanks buddy.
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Can anyone explain this question..
Q: Which two addresses can be assigned to a host with a subnet mask of 255. 255. 254. 0? (Choose two. )
A. 113. 10. 4. 0
B. 186. 54. 3. 0
C. 175. 33. 3. 255
D. 26. 35. 2. 255
E. 17. 35. 36. 0
Answer: BD
@matt:
A. Incorrect: 113.10.4.0 is a subnet address (i.e.: 113.10.0.0, 113.10.2.0, 113.10.4.0, 113.10.6.0, etc)
B. 186.54.3.0 – is a correct host address for mask 255.255.254.0 (net 186.54.2.0)
C. 175.33.3.255 – Incorrect. It is a broadcast address for subnet 175.33.2.0/23
D. 26.35.2.255 – is a correct host address for net mast 255.255.254.0 (net 26.35.2.0)
E. Incorrect. Look explanation for answer A.
@DimS
Thank you..
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Can some one please help me with this question!!!!
The IP address 194.168.32.0/24 is available for use by a new network.
What class of IP address has your network been allocated?
If the organisation uses a flat network without subnets then how many hosts can be
attached to the network? Explain you answer clearly.
You are now required to create 6 subnets by choosing the correct subnet mask.
Show clearly how your choice of subnet mask will generate the required subnets and
list the IP address range of each subnet.
Show the subnet address for each subnet and the broadcast address for each subnet.
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@Alan: The IP address 194.168.32.0/24
ans1: Class ‘C’ (first octet between 192 – 223)
ans2: 254 hosts or IPs (/24 indicates first three octets are in network portion )
ans3: 256/6 = 42.66 hosts (six uniform subnets cannot be created. It has to be VLSM ) lets assume we need 8 subnets then it would be like
…….: 256/8 = 32 hosts or IP per subnet
list of subnet:1) 194.168.32.0 == 194.168.32.31 (usable IP b/w 194.168.32.1 to 194.168.32.30)
2) 194.168.32.32 == 194.168.32.63 (usable ip again b/w subnet and broadcast)
3)194.168.32.64 == 194.168.32.95
4)194.168.32.96== 194.168.32.127
5) 194.168.32.128==194.168.32.159
6)194.168.32.160==194.168.32.191
7) 194.168.32.192==194.168.32.223
8) 194.168.32.224==194.168.32.255
Ans4: the starting ip is Subnet ID, the ending one is Broadcast ID and all other ip in between are usable.
Answer 5: The Subnet mask will be simply 255.255.255.224 because we know we got hosts per subnet by divideing the the given subnets required i.e. 8 so 255/8= 32 hosts
/25 gives you 128 hosts
/26 gives you 64 hosts
/27 gives you 32 hosts
It means our prefix changed from /24 to /27. Three bits of the last octet shifted to network portion….. 128+64+32 = 224
so the subnet mask you get is 255.255.255.224
Show clearly how your choice of subnet mask will generate the required subnets and
list the IP address range of each subnet.
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Why is the answer a also included .
http://tinypic.com/r/2lnye11/5
Why is the answer c .
http://tinypic.com/r/2yloizk/5
Can anybody explain ?
Thnx :)
Thanks 9tut.com It relly helped me to solved small small queries
Question 4 is a really messed up one. I just hope I never encounter it in the exam.
The word “SHOULD” confuses the hell out of the reader. It implies that you “could” set the subnet or broadcast address as assignable but you “shouldn’t”!
The fact of the matter is that you can never assign a subnet or a broadcast address into the DHCP pool, as the IOS doesn’t even provide you the tools to do that.
The command “network [ip_address][subnet_mask]” doesn’t leave you room for this error, at least as far as the CCNA curriculum is concerned. The only thing you could do wrong here is use a subnet mask which isn’t the right one for the range you want to use, but that would only modify the size of the pool.
You CAN’T use the “host” command if you used the “network” command, which is the only one we learned in CCNA for defining DHCP pools anyway (I believe that “host” command is CCNP-level).
Therefore the innuendo of the question’s statement which leaves the impression that you COULD actually assign a subnet or a broadcast address into the DHCP pool when you configure a DHCP server but you SHOULDN’T do it, is FALSE.
Even if you aren’t aware that those addresses are not valid IP addresses for hosts, the IOS doesn’t give you any chance to screw it up on this one.
On the other hand, answers E, F are ACTUALLY those which should have really counted as true (should the statement of the question have been interpreted as “what IPs you should never assign”), because as a network admin you truly have to take care that you exclude from the DHCP pool the static IP addresses of your network, by using the “ip dhcp exclude-address” first, and only after that define the DHCP pool.
So, just as a pointless rant, I believe that Q4 uses an unfortunate statement which leads to confusion and useless answers, as the user doesn’t get tested on any valuable practical knowledge.
But if that’s what they really use in the exam then we’ll probably have to stick with the answers given here, although I really hope I don’t get to see it. :)
Xallax
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In Question 10,
Would the following work?…
If you changed Switch1′s host ports to VLAN1,
and changed Switch2′s host ports to VLAN2,
then router’s LAN ports to-
to Switch 1 – 192.168.1.1/24
to Switch 2 – 192.168.2.1/24
Would this work?
I think it would work up until the point where either connection from a switch to the router was lost. What would happen at this point?
My guess is that if Host1 wanted to talk to Host4, and S1-R1 was down -
S1 would send it with 802.1Q to S2
S2 would then send it to R1
R1 would re-encapsulate it with a 802.1Q frame for VLAN2 and send it back to S2 for H4.
Am I correct?
or what would be the way to get that network working?
Thankyou for your time!
Bend
addressing sheme will be accepted if we will using one physical interface and 2 sub interfaces ,but if we will use 2 physical interfaces of router we must change address sheme ok
planning to take exam on tomorrow morning……any unexpected recent changes in ccna exam…can anyone help??
Question guys.I’m sitting for my exam soon. Does the question come out exactly the same as in IP addresses & all with this questions here in 9tut? need help. can anyone send me the latest dump to casstar91@gmail.com. Thank you so much for your time & help!!
RE: Anonymous
Vlan doesn’t matter at all in this situation. Only the IPs which are assigned on the router’s interfaces matter, and they exist within the same subnet. It should be 192.168.1.1 and 192.168.2.1.
where is the Q5 here??is that qtn is missing?if somebody know pls tell me…..
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CCNA exam on 5th dec ,any new questions in CCNA exam ohter than wat we see in 9tut or acme collisio
@CCNA guys plz answer this Q in the pic
http://img104.herosh.com/2011/12/03/484457891.jpg
and what is the effect of subnet-zero command when it is in use ??
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Refer to the exhibit. The networks connected to router R2 have been summarized as a
192.168.176.0/21 route and sent to R1. Which two packet destination addresses will R1 forward to R2?
A. 192.168.194.160
B. 192.168.183.41
C. 192.168.159.2
D. 192.168.183.255
E. 192.168.179.4
F. 192.168.184.45
Answer: BE why not (F) ALSO PLEASE FEED ME BACK
@as
“refer to the exhibit”…
192.168.176.0/21 means 192.168.176.0 ~ 192.168.183.255
A. 192.168.194.160
outside, wrong
B. 192.168.183.41
inside, good
C. 192.168.159.2
outside, wrong
D. 192.168.183.255
broadcast address, wrong
E. 192.168.179.4
inside, good
F. 192.168.184.45
outside, wrong
please read 9tut’s tutorial on subnetting, thank you
http://www.9tut.com/subnetting-tutorial
@eng-support
/27 means 8+8+8+3 bits.
/27 also means 255.255.255.224
this subnet allows us to segment a big network in smaller networks of 30 usable IPs each.
the subnets are like this:
x.x.x.0 ~ x.x.x.31
x.x.x.32 ~ x.x.x.63
…
add increment of 32
…
x.x.x.224 ~ x.x.x.255
also keep in mind that subnet zero is usable. what does that mean? it means that you are allowed to use the IP addresses on the first AND last subnets on the subnetted network.
looking at the image, my answers are:
A. 10.15.32.17 – assignable
B. 17.15.66.128 – multiple of 32, network address, non-assignable
C. 66.55.128.1 – assignable
D. 135.1.64.34 – assignable
E. 129.33.192.192 – multiple of 32, non-assignable
F. 192.168.5.63 – (multiple of 32) – 1, this is a broadcast address, non-assignable
@eng-support
regarding the routing question
take a look at the exhibit, it shows you 2 eigrp routes, both have equal metric values.
Answer D is correct. R3 would load-balance by sending half the packets to R1 and half to R2
@ xallax
about q 10,”with all hosts configured in the same VLAN” ,does it mean we dont need STP & TRunking.(ans B,D..
thaaaaaaaaaaaaanx
@z
if there was only 1 connection to the router then we wouldn’t need STP for that topology.
since all the hosts are on the same VLAN and there is not other VLAN in use we wouldn’t need VTP.
still, the router has 2 interfaces configured on the same subnet which is illegal.
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@ xallax
“if there was only 1 connection to the router then we wouldn’t need STP for that topology.”but i think in Q 10 we hv 2 connection to router –sw1 can get to router through sw2 or directly.
so, donnt we need STP?