CCNA – Subnetting Questions 2

thanks 9tut!=D

Hi there, can someone please send me the latest dumps of the 640-802 exam to (karrar.2003@yahoo.com). taking exam next week.

Thanks

for Q 10.
i found following to be best explanation:-

Which two addresses can be assigned to a host with a subnet mask of 255.255.254.0? (Choose two)

A. 113.10.4.0
B. 186.54.3.0
C. 175.33.3.255
D. 26.35.2.255
E. 17.35.36.0

Answer: B D

Using a subnet of 255.255.254.0 means there are 2*256 ip addresses available. That’s 512 total, and 510 available for hosts. In your example of the 186 network ranges…
186.54.0.0 – 186.54.1.255
186.54.2.0 – 186.54.3.255
Therefore, 186.54.3.0 is available for hosts.

In the 26 network ranges…
26.35.0.0 – 26.35.1.255
26.35.2.0 – 26.35.3.255
Therefore, 26.35.2.255 is available for hosts.(not occupied by broadcast or network address)

similarly you can verify networks given in options:- A, C , E are not correct as they are either broadcast addresses or network addresses.

q6 –/29 0,8,16,24,32,40,48,64,72,80,88,96,104,112,120,128,136,144,152,160,168,176,184,192,200, 208,216,224,232,240,248

q9 —-/28 is range size of 16 —- 0,16,32,48,64,80,96,112,128,144,160,176,192,208, 224,240 —-net address is 32 and default gateway is 33 — broadcast address is 47 –so
34 – 46 are free to use

Q10 — /23 so the last bit in the octet changes — if you have 2.0 net then the range includes 2.0 thru 2.255 and 3.0 thru 3.255 where the broadcast address is 3.255
The next range is 4.0 thru 5.255 where 5.255 is the broadcast address -
the range size is 512

The network default gateway applying to a host by DHCP is 192.168.5.33/28. Which option is the valid IP address of this host?

A. 192.168.5.55
B. 192.168.5.47
C. 192.168.5.40
D. 192.168.5.32
E. 192.168.5.14

Answer: C
It’s definitely B

1- Given the network address 10.0.0.0, a company is expanding to three new locations, such that:
Location 1 = 100 users
Location 2 =200 users
Location 3=300 users
What masks should be used in each location to accommodate the number of users. Write down the resulted subnet numbers for each location.

Hi,
i saw question
required point to point links 113,need to find the addressing scheeme with fewest networkds and addrss to be wasted
given answers are 10.10.0.0/18 255.255.255.252
10.10.0.0/25 255.255.255.252

10.10.0.0/23 255.255.255.252

10.10.0.0/16 255.255.255.252

and the answre is given as 10.10.0.0/23 can please why this anser is correct

Hi,

Can someone please send me the latest dumps of the 640-802 exam to (tomnick81@gmail.com).

Hi,
Can someone please send me the latest dumps of the 640-802 exam to (tomnick81@gmail.com).

Hi all, I am taking CCNA 640-802 exam first time on 30/05/2012. Could anyone please send me latest dumps which are valid for UK? My e-mail address is puneet_gill84@yahoo.co.uk. Many thanks.

answer to Q6 is wrong

1st subnet: 192.168.8.0
2nd subnet: 192.168.8.8
3rd subnet: 192.168.8.16
4th subnet: 192.168.8.24
5th subnet: 192.168.8.32
6th subnet: 192.168.8.40

answer is B. 192.168.8.41

Please read the question again. First line says it all…”The ip subnet zero command is not configured on a router.”

The “ip subnet zero” is not configured so the first subnet will start at 192.168.8.8 (ignoring 192.168.8.0).

So, the 6th subnet is 192.168.8.48 not 192.168.8.40 and the first usable IP address of 6th subnet is 192.168.8.49

@Abdul Fathah MK
So the answer of Q6 is C. 192.168.8.49 is absolutely Correct.

@Abdul
The ip subnet zero command is not configured on a router.
This means you cant use the 1st subnet.

Hi Can anybody send me latest dumps valid for usa to my mail id, basavarajpardi@gmail.com.
thank you

Pls can any body help me with the latest dumps on CCNA. I plan to take this exam in less than a month’s time. i have been studying but don’t have the dumps.

Pls can any body help me with the latest dumps on CCNA. I plan to take this exam in less than a month’s time. i have been studying but don’t have the dumps. Pls send to my mail realitychiboy@yahoo.com

I PASSED CCNA EXAM TODAY THANKS TO ALL MIGHTY ALLAH
960/1000

HI, can somebody help me with this problem? i really dont understand with this,,Thanks

Question 4

Refer to the exhibit. What is the most appropriate summarization for these routes?

A. 10.0.0.0/21
B. 10.0.0.0/22
C. 10.0.0.0/23
D. 10.0.0.0/24

@gilbert
look at the exhibit and see where the range starts (10.0.0.0) and where does it end (assume that 10.0.3.0 has a /24 mask because the other subnets have it; ends at 10.0.3.255)

the range is 10.0.0.0 ~ 10.0.3.255
you could turn it into bits… do the math… that is ugly and takes time… or you could just figure out how many bits do you need for the subnet mask

pay attention to the third byte. starts at 0, ends at 3.
question: what subnet would have these IPs on it: .0, .1, .2 and .3?
a subnet with a mask of /30 of course!

our question is about a subnet that starts at .0.0 and ends at .3.255
just subtract 8 from the subnet mask you figured out above (because the addresses start in the 3rd byte) and you end up with /22 :)
see? simple logic

Thanx xallax.. im going to take this coming july..

I passed my ccna exam today Praise be to God! Thank you Jesus! and thanks to 9TUT for the tutorials and explanations, great site and thanks to xallax for your explanations to questions and thanks to http://www.examcollection.com for the dumps. Pls guys lets donate and help to keep this site up!

48 ques for exams including 3 simulation, I had EIGRP, Acesslist2 and VTP. Make sure the practice the simulation, use packet tracer or gns3. Best wishes to all!

q7 The range for network 192.0.2.0/23 would be 192.0.2.0 – 192.0.3.255:

The IP given falls into the 192.0.2.0 network:

128 64 32 16 8 4 2 1
1 1 1 1 1 1 1 x /23 (this is focusing on the third octet only)
0 0 0 0 0 0 1 0 (decimal 2, from the IP we were given)
——————————-
0 0 0 0 0 0 1 0 = network 2 (or 192.0.2.0)

The increment will be 2, as the last bit borrowed in the third octet is decimal 2:

192.0.2.0 – 192.0.3.255 –> this is the range we’re working in
192.0.4.0 – 192.0.5.255
192.0.6.0 – etc.

The question asks which option is a valid IP address that can be assigned to a HOST?

A. 192.0.2.0
B. 192.0.2.255
C. 192.0.3.255
D. 192.0.4.0

Only answers A and C fall into this range, and A is the subnet (it’s not a valid host address). So, answer B is correct.

regarding your explaination for Gilbert why we have to subtract 8 from the subnet mask ?

why you choose 8?
is it because the addresses start in the 3rd byte and forth octet is 00000000

can someone explain question 7 with more explanations, such as showing the 1st ip for the 1st subnet, with he network address and the broadcast address. same example with 2nd and 3rd subnet. I really need help. I going to right my ccna in 8 days. thx.

u all r jst shit…
u dnt knw anything…

please re-explain question # 10. i’ll be very thankful

Dear angel im not clear about ur explaination of Q.10. how the range is in b/w 2.1 – 3.254
(im clear about starting range 2 bcoz increment is 2 but how dis range goes beyond 2.255 ..)
plz guide

please can any one explain q 3 more clearly
Question 3

Refer to the exhibit. Which mask is correct to use for the WAN link between the routers that will provide connectivity while wasting the least amount of addresses?

A. /23
B. /24
C. /25
D. /30

Answer: D

can someone please explain Q4 to me in detail, as i dont know what it means by saying “remove to left bits”

sorry thats two left bits

@khurrum
my way of doing it:
what’s the range? 10.0.0.0 to 10.0.3.255
0.0 to 3.255
if you were to use a subnet mask to fit this address space what would it be?
/24 (255.255.255.0) covers just .255
/23 (255.255.254.0) covers 0.0 to 1.255
/22 (255.255.252.0) covers 0.0 to 3.255 (this is the answer)

“We need to summarize 4 subnets so we have to move left 2 bits (2^2 = 4)”.
each subnet has the mask of 255.255.255.0
in binary that’s… 1111 1111.1111 1111.1111 1111.0000 0000
combining those 4 subnets requires a block of 4, 4 is 2 at the power of 2 (or “2^2″). that’s 2 extra bits for hosts.
delete 2 bits from the subnets (subnets on the right, hosts on the left. more 1s = more subnets, more 0s = more hosts)
result: 1111 1111.1111 1111.1111 1100.0000 0000
now count the 1s. there are 22 1s. that’s your answer

please read here to better understand subnetting: http://www.9tut.com/subnetting-tutorial

Hi everyone, i wrote my test yesterday and I passed it with a score of 867. Thanks to 9tut for the tutorials and clear explanations to the questions. I encourage 9tut.com users to reference this site to others.

Hi Juniormx,
Congratulations on achieving CCNA certification, can you please explain me why your score is not high like other and also about simulations which one came in your exam.

Awaiting for your reply @

qrazad@yahoo.com

Regards,

hey all, Can anyone of you please email me latest dump. i’m taking axams in less than a month, thanx in advance.

madzrhala@gmail.com

hi all can someone answer how many /30 nets can fit into /27

I did it!!..907..everyone needs to know subnetting if u want to be CCNA…there were about 5-7 question on subnetting..know the concepts…good luck to all!!..9TUT kicks!!

Please can any body provide me the latest dumps of CCNA.
I Plan to take exam in less than a month time.
Please send to my mail
ronnietherockstar@gmail.com

thanx

@xallax

You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while proving the maximum number of subnets. Which network address and subnet mask meet this requirement?

A-192.168.252.8 255.255.255.252
B-192.168.252.16 255.255.255.252
C-192.168.252.8 255.255.255.248
D-192.168.252.0 255.255.255.252
E-192.168.252.16 255.255.255.240

in this questions why they choose answer C not A or D can you clearfy it?

@xallax

The network administrator needs to address seven LANs. RIP version 1 is the only routing protocol in use on the network and subnet 0 is not being used. What is the maximum number of usable IP addresses that can be supported on each LAN if the organization is using one class C address block?

A-6
B-8
C-14
D-16
E-30
F-32

IS TRUE THE CORRECT ANSWER IS (C) can you explain it for me

i am can not understand some qutions pls help me someone

@smart86
subnet-zero is disabled, that means first and last subnets are unsable.
the admin needs 7 subnets. how many subnets per total? 7+2 = 9
on a class C network you can have 1, 2, 4, 8, 16, 32, 64 subnets.
the admin needs 9 so there have to be 16 created.
each subnet has 256 : 16 = 16 IPs (0~15, 16~31 and so on)
each subnet has 14 usable IPs (take out subnet and broadcast addresses)
C is correct

@xallax

(how many subnets per total? 7+2 = 9)

why you add 2 to the 7 subnet?

@xallax

I know that I am asking too much but I hope you answering me soon

@smart86
told you already, subnet-zero has been disabled and that means that first and last subnets are unusable.
you cant divide the classful network into 8 subnets and use 7 as there have to be 2 subnets that arent in use.
7 needed + 2 unusable = 9

@xallax

thank you very much an I really appreciate your help in explaining any questions I posted

Q7 – 192.0.2.0 references a class C network.
How is it possible to use a /23 on a class C network , when a /24 is the default for a class C network.

please explain.

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