CCNA NAT SIM Question 2
Question
| You work as a network technician at 9tut.com. Study the exhibit carefully. You are required to perform configurations to enable Internet access. The Router ISP has given you six public IP addresses in the 198.18.32.65 198.18.32.70/29 range. 9tut.com has 62 clients that needs to have simultaneous internet access. These local hosts use private IP addresses in the 192.168.6.65 – 192.168.6.126/26 range. You need to configure Router1 using the PC1 console. You have already made basic router configuration. You have also configured the appropriate NAT interfaces; NAT inside and NAT outside respectively. Now you are required to finish the configuration of Router1. |
Solution
Note: If you are not sure how NAT & PAT work, please read my Network Address Translation NAT Tutorial. You can download a similar sim to practice here: http://www.9tut.com/download/9tut.com_CCNA_NAT_sim_question.zip
The company has 62 hosts that need to access the internet simultaneously but we just have 6 public IP addresses from 198.18.32.65 to 198.18.32.70/29 => we have to use NAT overload (or PAT)
Double click on PC1 to access Router1′s command line interface
Router1>enable
Router1#configure terminal
Create a NAT pool of global addresses to be allocated with their netmask (notice that /29 = 248)
Router1(config)#ip nat pool mypool 198.18.32.65 198.18.32.70 netmask 255.255.255.248
Create a standard access control list that permits the addresses that are to be translated
Router1(config)#access-list 1 permit 192.168.6.64 0.0.0.63
Establish dynamic source translation, specifying the access list that was defined in the prior step
Router1(config)#ip nat inside source list 1 pool mypool overload
This command translates all source addresses that pass access list 1, which means a source address from 192.168.6.65 to 192.168.6.126, into an address from the pool named mypool (the pool contains addresses from 198.18.32.65 to 198.18.32.70)
Overload keyword allows to map multiple IP addresses to a single registered IP address (many-to-one) by using different ports
The question said that appropriate interfaces have been configured for NAT inside and NAT outside statements.
This is how to configure the NAT inside and NAT outside, just for your understanding:
Router1(config)#interface fa0/0
Router1(config-if)#ip nat inside
Router1(config-if)#exit
Router1(config)#interface s0/0
Router1(config-if)#ip nat outside
Before leaving Router1, you should save the configuration:
Router1(config)#end (or Router1(config-if)#end)
Router1#copy running-config startup-config
Check your configuration by going to PC2 and type:
C:\>ping 192.0.2.114
The ping should work well and you will be replied from 192.0.2.114
Other lab-sims on this site:
CCNA Configuration SIM Question (RIPv2 SIM)
I understand everything, except where the wildcard mask of 63 came from. Explain..?
Rajiv
The Wildcard easy to be calculated :
255.255.255.255 – 255.255.255.192(/26 SM of private range)
the result will be = 0.0.0.63
The lab is not working with these commands still cant ping 192.0.2.114 ???????
Anyone can help me plzz !
@ noha the attached lab has diff. ip’s so do the same commands by the ip’s given in the lab and it will work
ip nat pool mypool 198.18.184.105 198.18.184.110 netmask 255.255.255.248
access-list 1 permit 192.168.100.16 0.0.0.15
ip nat inside source list 1 pool mypool overload
int f0/0
ip nat inside
int s0/0
ip nat outside
copy run startup
ping 192.0.2.114
good luck !!!
@muhamed
I have followed your commands but nothing is pinging again !?
@ noha
i did it again and it works
@muhamed try it with a netmask of 0.0.0.0
@Anonymous
Chck you int fa0/0 an s0/0 on “sh run” if its correct
fa0/0
inside
s0/0
outside
Dear friend my comment on “Ahmed B. Hameed March 10th, 2015″ is wrong so don’t take it attention.
9tut Administrations please can you remove is please ? the configuration answer is perfect and worked normally………
@Ahmed B. Hameed: We removed that comment.
I passed today with 31/03 986/1000 in London – still valid. The questions 90% from 9tut and some you can find in the other VCE file on the internet. ACL, ACL2 and EIGRP but with different names and IPs for the hosts and others. You can easily pass if you study a few times this questions from 9tut plus a little from books(very important to know about ospf, eigrp, vlans and others). I can help with any tips if somebody wants.
michael.pat86@ymail.com
Thanks 9tut and thanks God!!!
Given that the LAN on the left hand side must support 62 clients, then the /26 subnet is insufficient. The /26 subnet provides 62 valid IP addresses. 1 IP address needs to be assigned to the Router (Router1 in this case), leaving only 61 valid IP addresses for the Clients (local hosts). In this case, the subnet mask must be at least /25.
Thanks 9tut. Only 9tut.
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but in practice sim the subnet mask is not provided…
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These local hosts use private IP addresses in the 192.168.6.65 – 192.168.6.126/26 range.
/26 => 255.255.255.192 => wild mask 0.0.0.63
bye bye
After spending few hours to troubleshoot this issue, I have found that the ISP router don’t have any route for 198.18.6.64/29 network
Need to remove current static route from ISP router and add route as – 198.18.6.64/29 via 192.0.2.113
click on ISP router – (you need to configure route on GUI)
Go to Config
Go to Routing and then Static
Remove existing route and add the route for 198.18.6.64/29
It works for me….Thanks
I son’t get something. If I open the CCNA NAT Sim question it already pings 192.0.2.114 without needing to configure anything. Also I don’t see the NAT inside and NAT outside configuration on the interfaces. Is it normal?
Apart from that I get the answer, it all makes sense.
Oh no, sorry. I tried on the wrong PC> Now I get it :)
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SEND ME NEW DUMPS AT nicefellow11@gmail.com.Thanks.
adnan
Did Anyone meet this question in the CCNA 120-220 Exam..??
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overload is no necessary
password ‘cisco’ doesn’t work for ISP router?
access-list 1 permit 192.168.6.64 0.0.0.63 how its get 192.168.6.64? omg it confused me
whereis the initial config
can someone please tell me that for the multiple choice questions ,if we i select only 2 out of 3 correctly . Do i lose full marks for the question or i get some amount of marks ?
hello @Boon Fong let me try to help you ok.
/26 means that the subnetmask is 255.255.255.192 and with this subnetmask the block size is
256-192=64 so when you look at that network range u will see that this fall into the network address of 192.168.6.64 because you will increment the first network add with 64(le block size) to get the second network address
and from this we know that the wildcard mask is block size – 1 which means 64-1 =63(wildcard mask)
i hope you will understand . thanks
Hello all.
NAT SIM Question included in ccna 200-120 exam?
PLEASE i need urgent response. Thanks in advance