CCNA – Drag and Drop 1
Here you will find answers to drag and drop Questions
Question 1:
A dental firm is redesigning the network that connects its three locations. The administrator gave the networking team 192.168.164.0 to use for addressing the entire netwok. After subnetting the address, the team is ready to assign the addresses. The administrator plans to configure ip subnet-zero and use RIP v2 as the routing protocol. As a member of the networking team, you must address the network and at the same time conserver unused addresses for future growth. With those goals in mind, drag the host addresses on the left to the correct router interface. Once of the routers is partially configured. Move your mouse over a router to view its configuration. Not all of the host addresses on the left are necessary.
Answer:
Explanation:
In short, we should start calculating from the biggest network (with 16 hosts) to the smallest one using the formula 2n – 2 (n is the number of bits we need to borrow).Therefore:
16 hosts < 25 – 2 (we need to borrow 5 bits -> /27)
11 hosts < 24 – 2 (borrow 4 bits -> /28)
5 hosts < 23 – 2 (borrow 3 bits -> /29)
From the available ip addresses, we see that each of them has only one suitable solution (they are 192.168.164.149/27,192.168.164.166/28 and 192.168.164.178/29)
The smallest network is the Floss S0/0 which only requires 2 hosts = 22 – 2 (need to borrow 2 bits ->/30). There are 2 suitable answers: 192.168.164.189/30 and 192.168.164.188/30 but notice that 192.168.164.188/30 is the network address so we can not use it (because 188 = 4 * 47) -> we have to choose 192.168.164.189 as the correct solution.
In fact, it is not the formal way to solve a VLSM question so I recommend you to review your CCNA book if you haven’t grasped it well yet.
Question 2:
In order to complete a basic switch configuration, drag each switch IOS command on the left to its purpose on the right
Answer:
1) enable
2) configure terminal
3) hostname
4) Interface vlan 1
5) no shutdown
6) ip address
7) ip default-gateway
Question 3:
The Missouri branch office router is connected through its s0 interface to the Alabama Headquarters router s1 interface. The Alabama router has two LANs. Missouri users obtain Internet access through the Headquarters router. The network interfaces in the topology are addressed as follows: Missouri: e0 – 192.168.35.17/28; s0 – 192.168.35.33/28; Alabama: e0 – 192.168.35.49/28; e1 – 192.168.35.65/28; s1 – 192.168.35.34/28. The accounting server has the address of 192.168.35.66/28. Match the access list conditions on the left with the goals on the right. (Not all options on the left are used.)
Answer:
1) deny ip 192.168.35.16 0.0.0.15 host 192.168.35.66
2) deny ip 192.168.35.55 0.0.0.0 host 192.168.35.66
3) permit ip 192.168.35.0 0.0.0.255 host 192.168.35.66
Explanation:
1) The wildcard mask of the command “deny ip 192.168.35.16 0.0.0.15 host 192.16.35.66″ is 0.0.0.15, which is equal to network mask of 255.255.255.240 = /28. So the access list will deny all traffic from network 192.168.35.16/28 from accessing host 192.16.35.66, which is the IP address of accounting server.
2) The command “deny ip 192.168.35.55 0.0.0.0 host 192.168.35.66″ will deny host 192.168.35.55, which is a user and belongs to interface e0 of Alabama router (192.168.35.49/28) from accessing accounting server.
3) Because there is an implicit “deny all” command at the end of each access list so the command “permit ip 192.168.35.0 0.0.0.255 host 192.168.35.66″ will only let network 192.168.35.0/24 access accounting server whilst prevent traffic from other networks.
Question 4:
A host with the address of 192.168.125.34/27 needs to be denied access to all hosts outside its own subnet. To accomplish this, complete the command in brackets, [access-list 100 deny protocol address mask any], by dragging the appropriate options on the left to their correct placeholders on the right.
Answer:
1) ip
2) 192.168.125.34
3) 0.0.0.0
Full command: access-list 100 deny ip 192.168.125.34 0.0.0.0
Question 5:
Drag and drop the network user application to the appropriate description of its primary use (not all options are used)
Answer:
1) web browser
2) instant message
3) e-mail
4) database
5) collaboration
Question 6:
This topology contains 3 routers and 1 switch. Complete the topology.
| Drag the appropriate device icons to the labeled Device
Drag the appropriate connections to the locations labeled Connections. Drag the appropriate IP addresses to the locations labeled IP address |
(Hint: use the given host addresses and Main router information)
To remove a device or connection, drag it away from the topology.
Use information gathered from the Main router to complete the configuration of any additional routers. No passwords are required to access the Main router . The config terminal command has been disabled for the HQ router. The router does not require any configuration.
Configure each additional router with the following
| Configure the interfaces with the correct IP address and enable the interfaces.
Set the password to allow console access to consolepw Set the password to allow telnet access to telnetpw Set the password to allow privilege mode access to privpw |
Note: Because routes are not being added to the configurations, you will not be able to ping through the internetwork.
All devices have cable autosensing capabilities disabled.
All hosts are PC’s
Answer:
View full explanation of this question here
Hi 9tut:
Sorry to ask but in Q6 how do u get the increment 16?
Why do u multiple 16 *11
Increment: 16 (/28 = 255.255.255.240 or 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.168.152.176 (because 176 = 16 * 11 and 176 < 177)
Broadcast address: 192.168.152.191 (because 191 = 176 + 16 – 1)
Thank u
CP
Hi 9tut
I get it 240 = 1111 0000 4 host increment 2^4=16
but I still ?? on Network address: 192.168.152.176 (because 176 = 16 * 11 and 176 < 177)
Why do u multiple to 11 in 176 = 16 * 11
and in:
Network address: 192.168.152.128 (because 128 = 16 * 8 and 128 < 129)
Why do we multiple to 8 in 128 = 16 * 8
Thank u
CP
Hi 9tut
Sorry is me again. I have the explanation from your answer on march 8 2011
Thank you so much
CP
Do these questions look like the ones in the real exam?
q. no. 4.
was in test icnd2. date 09/02/2012.
Thanks, question 1 is wrong on the Colisio dump
In question I don’t understand why 192.168.164.188/30 is the right answer for the link between the routers. How do we know it is a network address with the given information? Where did the 4*47 come from? Can some one explain this to me.
I figured it out. The increment of /30 is 4 and all network addresses in this mask are a multiple of 4 and can not be used. Any address that is a multiple of the increment -1 also cant be used because those are broadcast addresses.
please send me the latest dumps.. Thanks. rjay_1215@yahoo.com
can any one tell me how could i learn subneting so easy
Hello to all
Very usefull site.Note 9,9 (from 10) because 10 is for teachers and here we are all students. I’ll have CCNA exam on Monday 12.03. Wish me luck!
What is the number of access list that can be applied to an interface.
@ How many…… We can use one access list per direction per layer 3 protocols.
For question No 4 explanation the full command is
access-list 100 deny ip 192.168.125.34 0.0.0.0 ANY
The any at last is missing and it uses list number 100 which make it extended list.
I want to sit April first week 2012 for CCNA please send me latest dump,
poresh_05@yahoo.com
@please how many access lists can u apply on any interface?
You can apply as many as you want but you really only want to apply 1 per interface.
i will be written my ccna on Friday can any one send me the latest dumps thanks in advance.
i will be written my ccna on Friday can any one send me the latest dumps thanks in advance,my mail is naana10000@ymail.com
can any one tell me abt hotcerts.com
@xallax or @anyone who has an idea about this
I have a question regarding drag and drop questions. Say for example the drag and drop question is comparing the differences between RIPv1 and OSPF. In the actual test do we have to place all the characteristics of RIPv1 in a certain order in boxes under RIPv1 and the same for characteristics of OSPF in the boxes under OSPF ?
@raj
the order matters only on questions where it is specified (example: boot sequence)
if you are told to drag all the characteristics of on group (such is the case on your question) then the order does not matter
@xallax
I guess then that is a scoring glitch in the question dump.
@raj
im talking about the real exam, not simulations :)
Can any one please explain the soultion to Q4!! i feel that the host will be denied access outside its subnet as well as within its subnet!!
Please explain!!
Regarding Q1, I have a question that if there are 6 hosts attached to the switch on the left, network address which with mask 255.255.255.248 can not be used any more, right?
Regard
@Saurabh
traffic which transmitting in a same subnet would use MAC address…
Can someone send me the latest exam dump please ?
Please send to my email annbaktiar@mail2student.com
I will be taking the exam end of April.
Many thanks
I have exam tomorrow :) I am scared and i feel that I have many gaps in knowledge. Great website… helped me more than books. Thank you guys for commenting as well
In Q1, how did you get 47 on (because 188 = 4 * 47)?
it is so easy problem i deviosercd it after week of trying ::just change the option from the router in 192.168.1.1 and choose dynamic IP instate of static IP not from the mobile like we always do but from the wireless option the save changes and bake to mobile >>settings>>connectivity >> wifi>>and select network you use and click on forget if it in static IP and leave it if it was in dynamic IP then nothing browse the internet normally i have wave 525a0sorry for bad english language
Dear 9tut
First what you do is a great job, the question number 1 make my so confuse because the question said (The administrator plans to configure ip subnet-zero) and you said we cannot use 192.168.164.188/30 (notice that 192.168.164.188/30 is the network address), this make my more confuse please Explain that.
Thanks allot
Sir.saadelsayed@yahoo.com
@Best_Friend: Yes, we can’t assign 192.168.164.188 to a host because it is a network address. Notice that in a subnet, the network address and broadcast address can’t be used for host.
The “ip subnet-zero” allows the use of the first subnet. It does not allow us to use the network & broadcast addresses for hosts.
Praise be to Allah
I pass CCNA exam yesterday with 1000/1000 thanks for ALLAH, then the astonishing 9tut that really help me not to pass CCNA only but to help me to understand the CCNA very well and give me the best experience as CCNA candidate.
-access-list 100 permit ip any any –>real work to allow hosts in core and network to access Public Web Server.
-if you type the access-list wrong you can create another one with a different number and apply it again on the target interface.
-focus on configuration revision number in VTP LAB.
Thank you again 9TUT
helllllo
need file for drag and drop to learning in house because idont have internet in house pls try to send to email meto343@yahoo.com thanks for all
Hello Guys, I m Going To attend CCNA exam Tomorrow.. Thanks 9tut…
Hi all, I am taking CCNA 640-802 exam first time on 30/05/2012. Could anyone please send me latest dumps which are valid for UK? My e-mail address is puneet_gill84@yahoo.co.uk. Many thanks.
Similar Q1 out in ICND2 today
in Q1 the ip-subnet zero is in use, we can use the network address.
Please send me latest dump thanks 4 all
ibr_2007@hotmail.com
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I PASSED CCNA EXAM TODAY THANKS TO ALL MIGHTY ALLAH
960/1000
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in the real exam , can i find question like Q6 ? :(
it’s complicated , and its confused me
nice ccna…
I passed my ccna exam today Praise be to God! Thank you Jesus! and thanks to 9TUT for the tutorials and explanations, great site and thanks to xallax for your explanations to questions and thanks to http://www.examcollection.com for the dumps. Pls guys lets donate and help to keep this site up!
48 ques for exams including 3 simulation, I had EIGRP, Acesslist2 and VTP . Make sure you practice the simulation, use packet tracer or gns3. Best wishes to all!
CCNA DRAG AND DROP QUESTION:
ADVANTAGE AND DISADVANTAGE of POINT TO POINT, CIRCUIT SWITCHED and PACKET SWITCHED
bandwidth, quality, delay, more flexibility, low speed, more complex, load, cost, limited flexibility, efficient
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