EIGRP Troubleshooting Sim
Question
Refer to the topology. Your company has connected the routers R1, R2 and R3 with serial links. R2 and R3 are connected to the switches SW1 and SW2, respectively. SW1 and SW2 are also connected to the routers R4 and R5.
The EIGRP routing protocol is configured. You are required to troubleshoot and resolve the EIGRP issues between the various routers. Use the appropriate show commands to troubleshoot the issues.
Instead of posting the output of “show run” commands we post here the commands entered on each router to reduce some useless lines. Also you can try solving questions by yourself before reading the answers.
| R1: int lo0 ip address 10.1.1.1 255.255.255.255 int e0/0 ip address 192.168.16.1 255.255.255.0 int s1/1 ip address 192.168.13.1 255.255.255.0 bandwidth 1000 int s1/3 ip address 192.168.12.1 255.255.255.0 ! router eigrp 1 network 192.168.12.0 network 192.168.13.0 network 192.168.16.0 |
R2: int lo0 ip address 10.2.2.2 255.255.255.255 int e0/0 ip address 192.168.123.2 255.255.255.0 int s2/1 ip address 192.168.12.2 255.255.255.0 ! router eigrp 1 network 10.2.2.2 0.0.0.0 network 192.168.12.0 network 192.168.123.0 |
R3: int lo0 ip address 10.3.3.3 255.255.255.255 int e0/0 ip address 192.168.123.3 255.255.255.0 int s2/1 ip address 192.168.13.3 255.255.255.0 ! router eigrp 1 network 10.3.3.3 0.0.0.0 network 192.168.13.0 network 192.168.123.0 |
| R4: int lo0 ip address 10.4.4.4 255.255.255.255 int lo1 ip address 10.4.4.5 255.255.255.255 int lo2 ip address 10.4.4.6 255.255.255.255 int e0/0 ip address 192.168.123.4 255.255.255.0 ! router eigrp 2 network 10.4.4.4 0.0.0.0 network 10.4.4.5 0.0.0.0 network 10.4.4.6 0.0.0.0 network 192.168.123.0 |
R5: int lo0 ip address 10.5.5.5 255.255.255.255 int lo1 ip address 10.5.5.55 255.255.255.255 int e0/0 ip address 192.168.123.5 255.255.255.0 ! router eigrp 1 network 10.5.5.5 0.0.0.0 network 10.5.5.55 0.0.0.0 network 10.10.10.0 0.0.0.255 network 192.168.123.0 |
R6: int lo0 ip address 10.6.6.6 255.255.255.255 int e0/0 ip address 192.168.16.6 255.255.255.0 ! router eigrp 1 network 10.6.6.6 0.0.0.0 |
Note: In the exam, this sim uses IOS version 15 so “no auto-summary” is the default setting of EIGRP. You don’t have to type it.
You can download the pkt file to practice here: http://www.9tut.com/download/9tut.com_CCNA_EIGRP_Troubleshooting_Sim.pkt
Question 1
The loopback interfaces on R4 with the IP addresses of 10.4.4.4/32, 10.4.4.5/32 and 10.4.4.6/32 are not appearing in the routing table of R5. Why are the interfaces missing?
A. The interfaces are shutdown, so they are not being advertised.
B. R4 has been incorrectly configured to be in another AS, so it does not peer with R5.
C. Automatic summarization is enabled, so only the 10.0.0.0 network is displayed.
D. The loopback addresses haven’t been advertised, and the network command is missing on R4.
Answer: B
Explanation
On R4 we see EIGRP is configured with AS 2 (router eigrp 2) while other routers are using AS 1 (router eigrp 1). Therefore R4 cannot see other routers and vice versa.
Question 2
Which path does traffic take from R1 to R5?
A. The traffic goes through R2.
B. The traffic goes through R3.
C. The traffic is equally load-balanced over R2 and R3.
D. The traffic is unequally load-balanced over R2 and R3.
Answer: A
Explanation
For this question we have to check the routing table of R1 to find out the answer. Use the “show ip route” command on R1 we will get something like this:
There are three interfaces on R5 which are Loopback0: 10.5.5.5 ; Loopback1: 10.5.5.55; Ethernet0/0: 192.168.123.5 and all of them are advertised via 192.168.12.2 so we can conclude traffic from R1 to R5 goes through R2 (192.168.12.2 is the IP address of S2/1 interface of R2).
Note: Maybe there is another version of this question in the exam in which the answer should be “The traffic is equally load-balanced over R2 and R3″. Therefore please check the “show ip route” output carefully to see if there are more than one route to the destination.
Question 3
Router R6 does not form an EIGRP neighbor relationship correctly with router R1. What is the cause for this misconfiguration?
A. The K values mismatch.
B. The AS does not match.
C. The network command is missing.
D. The passive-interface command is enabled.
Answer: C
Explanation
From the configuration of R6 we learn that R6 is missing “network 192.168.16.0″ command (the network between R1 & R6) under EIGRP so EIGRP neighbor relationship will not be formed between them.
Question 4
Study the following output taken on R1:
| R1#ping 10.5.5.55 source 10.1.1.1 Type escape sequence to abort. Sending 5, 100-byte ICMP Echos to 10.5.5.55, timeout is 2 seconds: Packet sent with a source address of 10.1.1.1 . . . . . Success rate is 0 percent (0/5) |
Why are the pings failing?
A. The network statement is missing on R5.
B. The loopback interface is shut down on R5.
C. The network statement is missing on R1.
D. The IP address that is configured on the Lo1 interface on R5 is incorrect.
Answer: C
Explanation
R1 does not advertise its loopback 0 (10.1.1.1) to EIGRP therefore a ping to destination 10.5.5.55 (R5) from 10.1.1.1 will not be successful because R5 does not know how to reply to R1.
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Qestion 4
I think the true answer Is
A : The network statement is missing on R5.
@DECO
Question 4 answer is C
R1 has to advertise its network for R5 to know how to reach it.
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@tunchi
Q4:you are right C is the answer cos R1 is not advertising its loopback.
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Question 3.
On router R6 at int e0/0 command “no shutdown” is missing
only R1 have “no shutdown” commands :)
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Hey everyone! Today I scored 100%! Thank you 9tut! I had ACL, ACL2 & EIGRP Lab Question (router eigrp 12 and different IP addresses).
I also had 2 questions,which I think, I’ve havent found on here , but I’ve seen them in Matthew .vce questions. Those were:
1.) Which 2 statments about the OSPF Router ID are true? (choose 2):
a.) It identifies the source of Type 1 LSA
b.) It should be the same on all routers in an OSPF routing instance
c.) By default, the lowest IP address on the router becomes the OSPF router ID
d.) The router automatically chooses the IP address of a loopback as the OSPF ROuter ID
e.) It is created using the MAC Address of the loopback interface
(Answers A, D)
2.) What are two benefits of using a single OSPF area network design? (choose two)
a.) It is less CPU intensive for routers in the single area.
b.) It reduces the types of LSAs that are generated.
c.) It removes the need for virtual links.
d.) It increases LSA response times.
e.) It reduces the number of required OSPF nieghbor adjacencies.
(Answer B, C).
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Regarding question 1, after doing the SIM I believe there are actually two correct answer’s, B + C. Answer of B only is however correct with regards to the prints shown above as they omitt the “auto-summary” command that’s included in the SIM.
Question 1
The loopback interfaces on R4 with the IP addresses of 10.4.4.4/32, 10.4.4.5/32 and 10.4.4.6/32 are not appearing in the routing table of R5. Why are the interfaces missing?
B. R4 has been incorrectly configured to be in another AS, so it does not peer with R5.
– true, R4 was set to AS-2, while R5 (and all other routers) are AS-1
C. Automatic summarization is enabled, so only the 10.0.0.0 network is displayed.
– true, in the downloaded SIM, “auto summary” command is applied to the R4 eigrp router config, so once the AS has been corrected, R5 shows a summarised EIGRP route of 10.0.0.0/8 via 192.168.123.4 (R4s fa0/0 interface). When “no auto-summary” was defined on R4 eigrp router config then the missing R4 loopback addresses where shown in R5s routing table.
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